sed 正则匹配

hover_sky

1. 
   
2. 
   
3. # tail -f /var/log/myout.log |sed -n '/.*301.*Moved.*Permanently/ {n;s#.*test.com/user/\(.*\)/my.jpg\(\?l=.\)#\1\2#p}'
   
4. 275/8280275/2337999/jpg/5518681?l=h
   
5. 865/8450865/2381058/jpg/5507828?l=a
   
6. 96/2162096/1135051/jpg/5518743?l=i
   
7. 827/6478827/2165863/jpg/5140518?l=j
   
8. 709/2617709/846298/jpg/5518038?l=j
   
9. 658/2239658/600160/jpg/5518692?l=h
   
10. 766/2532766/1854003/jpg/5517944?l=h
    
11. 971/8017971/2042696459/jpg/5511655?l=j
    
12. 764/8094764/2301871/jpg/5486294?l=j
    
13. 514/8034514/2043108668/jpg/5518074?l=g
    
14. 766/2532766/1854003/jpg/5517944?l=h
    
15. 891/4823891/1619388/jpg/5518061?l=j
    
16. 669/4153669/1392095/jpg/5518258?l=h
    
17. 471/8335471/2346266/jpg/5410620?l=d
    
18. 766/2532766/1854003/jpg/5517944?l=h
    
19. 766/2532766/1854003/jpg/5517944?l=h&start=3487900
    
20. 669/4153669/1392095/jpg/5518258?l=h
    
21. 79/8490079/2382692/jpg/5518888?l=h
    
22. 669/4153669/1392095/jpg/5518258?l=h
    
23. 548/8479548/2378834/jpg/5519248?l=i
    
24. 669/4153669/1392095/jpg/5518258?l=h
    
25. 836/8036836/2043105172/jpg/5519297?l=d
    
26. 397/5578397/2384773/jpg/5518907?l=a
    
27. 
    

复制代码

请问哪里有漏洞，导致&start=3487900也被匹配到\2 ,谢谢

yinyuemi

回复 1# hover_sky


    sed -n '/.*301.*Moved.*Permanently/ {n;s#.*test.com/user/\(.*\)/my.jpg\(\?l=.\).*#\1\2#p}'

hover_sky

回复  hover_sky


    sed -n '/.*301.*Moved.*Permanently/ {n;s#.*test.com/user/\(.*\)/my.jpg\(\? ...
yinyuemi 发表于 2011-10-11 12:32

    我的目的是完全排除带有start 的匹配


  我明白了

jason680

回复 1# hover_sky


>>    请问哪里有漏洞，导致&start=3487900也被匹配到\2 ,谢谢

&start=3487900
它是没有被(匹配到)替换掉,还留着.......
而不是被匹配到 \2

hover_sky

回复  hover_sky


>>    请问哪里有漏洞，导致&start=3487900也被匹配到\2 ,谢谢

&start=3487900
...
jason680 发表于 2011-10-11 13:13

    嗯，是的。但我改成

tail -f /var/log/myout.log |sed -n '/.*301.*Moved.*Permanently/ {n;s#.*test.com/user/\(.*\)/my.jpg\(\?l=.\)$#\1\2#p}'

却没有输出

hover_sky

回复  hover_sky


>>    请问哪里有漏洞，导致&start=3487900也被匹配到\2 ,谢谢

&start=3487900
...
jason680 发表于 2011-10-11 13:13

   

不明白了。我要输出的是\1 和 \2 ，那为什么不是匹配\1 和 \2 的也输出 ？

jason680

回复 6# hover_sky

置顶文....(仔细看看...)
shell基础十二篇  / shell基础十：sed
http://bbs.chinaunix.net/thread-452942-1-1.html

hover_sky

回复  hover_sky

置顶文....(仔细看看...)
shell基础十二篇  / shell基础十：sed
jason680 发表于 2011-10-12 11:05

    谢谢兄台，明白了，是部分替代。



    719/7673719/2386737/jpg/5524677/my.jpg?l=d&start=442761


    我想 s的正则不处理这种语句，可有办法？谢谢

hover_sky

我想实现
从

HTTP/1.1 301 Moved Permanently
Location: http://test.test.com/user/91/228 ... 5523442/my.Ajpg?l=h

提取得到  91/2280091/585567/jpg/5523442|?l=h

HTTP/1.1 301 Moved Permanently
Location: http://test.test.com/user/91/228 ... ?l=h&start=2345

这种则不提取

可以这个得到：

       tail -f /var/log/myout.log|grep -v start |sed -n 's#.*test.com/user/\(.*\)/my.Ajpg\(\?l=.\)\(.*\)#\1|\2#p;'



通过关键字301.*Moved.*Permanently的下一行来提取，类似如下，还没实现。在下面语句的后面加  |grep --line-buffer  -v start 则没有输出。
        tail -f /var/log/myout.log |sed -n '/.*301.*Moved.*Permanently/ {n;s#.*test.com/user/\(.*\)/my.Ajpg\(\?l=.\)#\1\2#p}'

jason680

回复 9# hover_sky

直接说清楚须求....
最原始的input及最后output...这样比较快,CU牛人一堆.