如何查找有可能换行的字段？

njuytwc

回复 9# ziyunfei

[user@wjj1 reopt-t]$ awk -v RS='N\n?I\n?m\n?a\n?g\n?=\n?0\n?' 'NR==2{print FILENAME}' *out
10t.out

不对呀，才出来一个，哎

where27

回复 11# njuytwc


   把NR改成FNR

njuytwc

回复 12# where27


    还是有问题，跟grep -o 'NImag=0' * 出来的个数一样，漏掉换行的，比如这样的


  69464,0.0005056,1.0033139,0.0000217,-0.1137817\Polar=132.7870208,-0.00
  3345963,57.0003033,1.4197513,0.0298337,87.2483149\PG=CS [SG(N5)]\NImag
  =0\\0.68517253,-0.00000067,0.02995292,-0.20126190,-0.00000035,0.201316
  01,-0.03499828,0.00000249,0.01407913,0.60380217,-0.00000250,-0.0007381

突然发现，所有文本文件的第一列是空的，是不是应该再改改？

where27

回复 13# njuytwc


    晕，问题一次说清楚啊
改了一下云飞的，试试吧

1. awk -v RS='N\n?[ \t]*I\n?[ \t]*m\n?[ \t]*a\n?[ \t]*g\n?[ \t]*=\n?0' 'FNR==2{print FILENAME}' *out

复制代码

njuytwc

回复 8# Shell_HAT


   所有文本文件第一列是空列。

Shell_HAT

回复 15# njuytwc

1. for file in *.txt; do
   
2.     echo $file: $(sed 's/^[\t ]\+//;:a;N;$!ba;s/\n//g' urfile' $file | grep -o 'NImag=0')
   
3. done

复制代码

njuytwc

回复 14# where27


    多谢，搞定了。