awk段落筛选

dashorc

如下格式的数据：
==== BEGIN [10.0.0.1] BEGIN ====
111111
222222
==== BEGIN [10.0.0.1] END ====


==== BEGIN [10.0.0.2] BEGIN ====
111111
222222
333333
==== BEGIN [10.0.0.2] END ====


==== BEGIN [10.0.0.3] BEGIN ====
111111
222222
444444
==== BEGIN [10.0.0.3] END ====

==== BEGIN [10.0.0.4] BEGIN ====
111111
222222
==== BEGIN [10.0.0.4] END ====


现在我想找出只包含111111和222222的IP来，请高手帮忙
好久没用AWK了，都忘记了

where27

1. awk -F"\n" -v RS= '$2==111111&&$3==222222&&NF==4{split($1,a,"[][]");print a[2]}' file

复制代码

MeaCulpa

无数关联数组的例子了，不多说了••••••

rigeldeneb

1. BEGIN{RS=""; FS="\n"; two="222222"; one="111111"}
   
2. {
   
3. a = 0
   
4. for (i = 2; i < NF; ++i){
   
5.         if ($i != two && $i != one){
   
6.                 a = 1
   
7.         }
   
8. }
   
9. if (a){
   
10.         match($1, /\[.*\]/)
    
11.         print substr($1, RSTART + 1, RLENGTH -2)
    
12. }
    
13. }

复制代码

zhaopingzi

$  awk -vRS="" -vFS="\n" '$2==111111&&$3==222222&&NF==4{print $1}' nn|sed 's/[^0-9.]//g'
10.0.0.1
10.0.0.4

zhaopingzi

$  awk -vRS="" -vFS="\n" '$2==111111&&$3==222222&&NF==4{print $1}' file|sed 's/[^0-9.]//g'
10.0.0.1
10.0.0.4