怎么取出这样的文本中-i后面的字段？

ccc77

文本示例如下：
#!/bin/sh
exec 2>&1
exec setuidgid apache /usr/libexec/rrd/acquire-aggregate-generic -i affiliate  -a 239.11.50.5:8102
sleep 2
#!/bin/sh
exec 2>&1
exec setuidgid apache /usr/libexec/rrd/acquire-apache
sleep 2
#!/bin/sh
exec 2>&1
exec setuidgid apache /usr/libexec/rrd/acquire-cheetah -i cheetah -a 239.11.50.5:8042
sleep 2
#!/bin/sh
exec 2>&1
exec setuidgid apache /usr/libexec/rrd/acquire-aggregate-generic -a 239.11.60.5:5002 -e 'YSM::Monitor:H::Emitter::Stat' -i datahighway-emitter-by-host
sleep 2
#!/bin/sh
exec 2>&1
exec setuidgid apache /usr/libexec/rrd/acquire-distro-locks -a 239.11.50.5:8057 -i distro-locks
sleep 2


怎么取出这样的文本中-i后面的字段？

比如这里我需要：
affiliate  
cheetah
datahighway-emitter-by-host
distro-locks

suifeng2012

awk -F'-i ' '{print $2}' <txt |cut -d' ' -f1|sort|uniq

suifeng2012

改进一下:

awk -F'-i ' '{print $2}' <text.txt |cut -d' ' -f1|sed '/^$/d'

sak000

1. fp = open (file, "r")
   
2. for line in fp.readlines():
   
3.     if re.search ('-i', line):
   
4.         line = re.sub (r'^.*-i', '', line)
   
5.         line = re.sub (r'-.*$', '', line)
   
6.         print line.strip()
   

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fuliangcheng

#file for find str which specified by user
import re
f = file('file_test1.txt')
result = []
for line in f:
    s = []
    if re.search('-i', line):
        s = line.split()
        result.append(s[s.index('-i')+1])
        #print line,
        #print s[s.index('-i')+1],
        #print '\n'
print result   
        
        
结果：['affiliate', 'cheetah', 'datahighway-emitter-by-host', 'distro-locks']

inpool

1. result = []
   
2. for line in open('text.txt'):
   
3.     tmplist = line.split()
   
4.     if '-i' in tmplist:
   
5.         result.append(tmplist[tmplist.index('-i') + 1])
   
6. print result

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