请教一个sed问题

yuipr

  <project name="R7627A/device/common" path="device/common" revision="31b0557eecd8d45728f3d65977512a1d2087c410"/>
  <project name="R7627A/device/htc/common" path="device/htc/common" revision="867f8b454d754ff496b66527407753c451f54277"/>
  <project name="R7627A/device/htc/passion" path="device/htc/passion" revision="15ef3de8a2b15686bc0ea7ea4b802ae4af5a72ba"/>
  <project name="R7627A/device/htc/passion-common" path="device/htc/passion-common" revision="4fc91886b53b013b38b7cfc67fd35710207dc875"/>
  <project name="R7627A/device/qcom/common" path="device/qcom/common" revision="f9961e23e8a72452a2a5d9d49fb27c1cd23a5fcc"/>
  要将上面行中的revision后面的都去掉．变成下面的结果，用sed,awk应该怎么实现？
<project name="R7627A/device/common" path="device/common"　/>

yinyuemi

s/revision=[^/]\+//

yuipr

yinyuemi 发表于 2012-03-22 13:43
s/revision=[^/]\+//

这是可以的，还是不太明白你写的这个，能给解释下么
我刚开始是用的sed 's/revision.*//g' 发现这样把/>也给去掉了．

yinyuemi

回复 3# yuipr


    .*是贪婪匹配

yuipr

s/revision=[^/]\+//
能把你这个给解释下么

yinyuemi

回复 5# yuipr


    [^/]匹配非'/'的字符
   \+  匹配大于等于1个字符

jiejie455

sed 's@revision.*\/@@'

yuipr

yinyuemi 发表于 2012-03-22 13:57
回复 5# yuipr

明白了，谢了