【请教】shell字符串操作

phenix_yw

如何从一个单词集中删除指定的单词，如
STR_ALL="Tom Jack Lily Eye"
STR_SKIP="Lily Jack"
如何从STR_ALL中剔除STR_SKIP中的字符？

yinyuemi

回复 1# phenix_yw

1. for word in $STR_SKIP; do STR_ALL=${STR_ALL/ ${word}/}; done; echo $STR_ALL
   
2. Tom Eye

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phenix_yw

回复 2# yinyuemi

有点小问题，第一个单词无法删除，如STR_SKIP="Tom Lily Jack"，结果仍然是Tom Eye
   

yinyuemi

回复 3# phenix_yw


    STR_ALL=${STR_ALL/${word}/}

jiejie455

1. #!/bin/bash
   
2. 
   
3. STR_ALL="Tom Jack Lily Eye"
   
4. STR_SKIP="Lily Jack"
   
5. 
   
6. skip=(${STR_SKIP})
   
7. 
   
8. for i in ${skip[*]}
   
9. do
   
10.         STR_ALL=$(sed "s/\<$i\>//g" <<<"$STR_ALL")
    
11. done
    
12. 
    
13. echo $STR_ALL
    

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firefoxbug

1. #!/bin/bash
   
2. 
   
3. STR_ALL="Tom Jack Lily Eye"
   
4. STR_SKIP="Lily Jack"
   
5. 
   
6. for word in $STR_SKIP       
   
7. do
   
8.         STR_ALL=`echo "$STR_ALL"  | sed "s/$word//g"`
   
9. done
   
10. 
    
11. STR_ALL=`echo "$STR_ALL" | tr -s ' '`
    
12. echo "$STR_ALL"
    

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jason680

回复 1# phenix_yw

$ echo $STR_ALL | sed -r "s/`echo $STR_SKIP | sed 's/ /|/g'`//g;s/ +/ /g"
   

sunceenjoy

#!/bin/bash
STR_ALL="Tom Jack Lily Eye"
STR_SKIP="Lily Jack"
for word in $STR_ALL
do
        if ! echo $STR_SKIP | grep -q -w $word
        then
           echo -n $word" "
        fi
done

Gubuntu

1. root@osssvr-1 # echo $STR_ALL | xargs -n 1 | egrep -v `echo $STR_SKIP | sed 's/ /|/g'`
   
2. Tom
   
3. Eye
   
4. root@osssvr-1 #

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Gubuntu

少了一步：

root@osssvr-1 # echo $STR_ALL | xargs -n 1 | egrep -v `echo $STR_SKIP | sed 's/ /|/g'` | xargs
Tom Eye
root@osssvr-1 #