数组

puxiaohua

Q5581-01% cat aa
F130086T2F|U131086T2F|P132086T2F

我想取aa里面的几个名字F130086T2F,U131086T2F,P132086T2F放到数组里面,

set llot = `sed -n 1p $locdir/aa`
echo "$llot"
awk 'BEGIN{split("'$llot'",status,"|");}'
for i in ${status[*]}
  do
    echo $i;
  done

运行出来:

for: Command not found
do: Command not found
i: Undefined variable

blackold

回复 1# puxiaohua


    太乱了。

awk 那行就错了吧。

yinyuemi

回复 1# puxiaohua


    awk的数组不能拿到bash中用

puxiaohua

其实很简单

aa这个文件内容:
F130086T2F|U131086T2F|P132086T2F

我就想取到F130086T2F,U131086T2F,P132086T2F这三个文件方到数组中,怎么弄

Shell_HAT

1. n=0
   
2. for line in `sed 's/|/\n/g' urfile`
   
3. do
   
4.     status[$n]=$line
   
5.     let n+=1
   
6. done
   
7. echo ${status[0]}
   
8. echo ${status[1]}
   
9. echo ${status[2]}
   

复制代码

puxiaohua

echo "$llot"
f=()
echo  ${f[*]}| awk 'BEGIN{l=split("'$llot'",status,"|");for (i=1;i<=l;i++)  print status[i]}'


运行结果
F130086T2F|U131086T2F|P132086T2F
Badly placed ()'s

Shell_HAT

回复 6# puxiaohua


    5楼代码结果如何？

puxiaohua

set llot = `sed -n 1p $locdir/aa`
echo "$llot"
for line in `sed 's/|/\n/g' $locdir/aa`

do

    status[$n]=$line

    let n+=1

done

echo ${status[0]}

echo ${status[1]}

echo ${status[2]}


运行结果:
Q5581-01% ./bb
F130086T2F|U131086T2F|P132086T2F
for: Command not found
do: Command not found
line: Undefined variable

seesea2517

回复 8# puxiaohua


    玩笑开大了

yinyuemi

回复 1# puxiaohua

1. status=($(echo 'F130086T2F|U131086T2F|P132086T2F' |sed 's,|, ,g'))
   
2. echo "${status[*]}"
   
3. F130086T2F U131086T2F P132086T2F
   

复制代码