获取最后一个数组

atyu30

    for value in oidlist:
        result = netsnmp.snmpwalk(value, Version = 2, DestHost = "atyu30", Community = "public")
        slist.append(list(result))
        print slist



a+b+c ......

[['0.02', '0.11', '0.09']]
[['0.02', '0.11', '0.09'], ['2257']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0']]
[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0'], ['48886214', '526525664', '0', '0']]


需要获取最后的那个数组

[['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0'], ['48886214', '526525664', '0', '0']]

cdtits

循环结束时，slist 不就是最后的结果么？

atyu30

我只要最后那一个长的，前面的忽略

cdtits

貌似这时应该是：

1. slist = [['0.02', '0.11', '0.09'], ['2257'], ['1417264'], ['2238014'], ['380180'], ['1642000'], ['8167452'], ['5692976'], ['48886214', '1557316605', '0', '0'], ['48886214', '526525664', '0', '0']]

复制代码

atyu30

实际运行结果不是这样的

atyu30

问题解决


    for value in oidlist:
        result = netsnmp.snmpwalk(value, Version = 2, DestHost = "10.0.20.79", Community = "public")
        slist.append(list(result))
    print slist