这提示消息截断 貌似数据没收全 怎么该

嘉伟w

1. def SendAndRecv(uin, cmd, req, rsp):
   
2.     uiLength=req.ByteSize() + 20
   
3.     uiUin=uin
   
4.     ushVersion=0
   
5.     iRetVal=0
   
6.     ushZoneID=0
   
7.     ushCmdID=cmd
   
8.     ushCheckSum=0
   
9. 
   
10.     buff = struct.pack("!IIHiHHH", uiLength, uiUin, ushVersion, iRetVal, ushZoneID, ushCmdID, ushCheckSum);
    
11.     buff += req.SerializeToString()
    
12. 
    
13.     sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM);
    
14.     sock.settimeout(5)
    
15.     sock.connect(ADDR)
    
16.     sock.sendall(buff)
    
17. 
    
18.     buff = sock.recv(64 * 1024)
    
19. 
    
20.     sock.close()
    
21. 
    
22.     print struct.unpack("!IIHiHHH", buff[0:20]);
    
23. 
    
24.     rsp.ParseFromString(buff[20:])
    

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这提示消息截断 貌似数据没收全 怎么该    帮个忙

嘉伟w

{:3_186:}有木有

106033177

回复 1# 嘉伟w

1. sock.connect(ADDR)
   
2. while 1:
   
3.   d = sock.recv(64 * 1024)
   
4.   if not d: break
   
5.   else: buf +=d
   

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