shell 求助 awk内嵌sed处理 没达到效果

uplogin

367222 order_33495993_20110613_20111111_27.csv
366359 order_33495993_20110613_20111111_27.csv
365496 order_33495993_20110613_20111111_27.csv
364633 order_33495993_20110613_20111111_27.csv
363770 order_33495993_20110613_20111111_27.csv
362907 order_33495993_20110613_20111111_27.csv
362044 order_33495993_20110613_20111111_27.csv
361181 order_33495993_20110613_20111111_27.csv
330473 order_33495993_20110613_20111111_27.csv
329610 order_33495993_20110613_20111111_27.csv
328747 order_33495993_20110613_20111111_27.csv
187656 order_33495993_20100517_20100910_27.csv
186838 order_33495993_20100517_20100910_27.csv
141798 order_33495993_20100517_20100910_27.csv
140980 order_33495993_20100517_20100910_27.csv
140162 order_33495993_20100517_20100910_27.csv
139345 order_33495993_20100517_20100910_27.csv
138528 order_33495993_20100517_20100910_27.csv
以上是bad.list的内容
我想删除对应文件的对应行号的内容
空格隔开 两边分别是要删除的行号和文件名
awk '{ system("sed -i " $1"d " $2)}' bad.list 这是我的命令 但是没能实现功能
版本是这个：
GNU Awk 3.1.5
Copyright (C) 1989, 1991-2005 Free Software Foundation.

rdcwayx

这个命令没问题。
查查ni的系统awk 版本。

uplogin

回复 2# rdcwayx


    版本是这个

GNU Awk 3.1.5
Copyright (C) 1989, 1991-2005 Free Software Foundation.

jason680

回复 3# uplogin

it work fine on Ubuntu 11.10

$ cat 5.txt
1
2
3
4
5

$ cat bad.list
3 5.txt
1 5.txt

# using echo check everything
$ awk '{system("echo sed -i "$1"d "$2)}' bad.list
sed -i 3d 5.txt
sed -i 1d 5.txt

$ awk '{system("sed -i "$1"d "$2)}' bad.list

$ cat 5.txt
2
4
5

$ awk -W version
GNU Awk 3.1.8
Copyright (C) 1989, 1991-2010 Free Software Foundation.
...

hbmhalley

while read a b; do sed -i -- ${a}d "$b"; done <bad.list

uplogin

回复 4# jason680


    sed -i 367222d order_33495993_20110613_20111111_27.csv
sed -i 366359d order_33495993_20110613_20111111_27.csv
sed -i 365496d order_33495993_20110613_20111111_27.csv
sed -i 364633d order_33495993_20110613_20111111_27.csv
sed -i 363770d order_33495993_20110613_20111111_27.csv
sed -i 362907d order_33495993_20110613_20111111_27.csv
sed -i 362044d order_33495993_20110613_20111111_27.csv
sed -i 361181d order_33495993_20110613_20111111_27.csv
我加了echo 执行结果 是这个 貌似正常啊 为什么去掉echo 源文件 依旧没有改变呢?
awk '{system("echo sed -i "$1"d "$2)}' bad.list