怎么处理一段数据中最后一个字段的数据

yokto2012

回复 10# dn833


   嗯，学习了
同问一个跟此贴反向的问题，如果要是对一段数据中最后一个字段列出，而不是删除，要怎样做的？

dn833

那就这么搞吧
grep -Po '(?<=##)[^#\n]+$'

dn833

奇怪了。。。。代码里不能以+$'结尾。。。。

a774050174

回复 12# dn833
awk -F'##' '{print $NF}' file
   

dn833

回复 14# a774050174


呵呵还是awk用着爽，不用去考虑复杂的正则匹配

blackold

回复 13# dn833


    可以的。

dn833

回复 16# blackold


   
那也行是我家里电脑的问题？？？12楼的代码只要放到[code][code]里就把最后3个字符给吃了

blackold

回复 17# dn833


    哦，\n应该不能放在[]内。

yokto2012

呵呵,多谢各位解答,学习了

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