求一个shell,根据IP和掩码位计算出网段

qq312873977

回复 2# dn833
好方法


   

mcshell

貌似大牛都是 凌晨出来写code

qq312873977

这个也行

1. #!/bin/bash
   
2. 
   
3. ip=`echo $1 | cut -d '/' -f1`
   
4. mask=`echo $1 | cut -d '/' -f2`
   
5. intIP=`echo $ip|awk -F'.' '{print $1*(256^3) + $2*(256^2) + $3*256 + $4}'`
   
6. resultIP=$((intIP|(2**(32-mask)-1)))
   
7. echo $ip-$((resultIP>>24)).$((resultIP>>16&0x00FF)).$((resultIP>>8&0x0000FF)).$((resultIP&0x000000FF))
   

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seeLnd

1. #!/bin/bash
   
2. 
   
3. while read line
   
4. do
   
5.   subnet=$(echo "$line" | awk -F'[/;]' '{print $1}')
   
6.   mask=$(echo "$line" | awk -F'[/;]' '{print $2}')
   
7.   subnet_t=$(printf '0x%.2x%.2x%.2x%.2x\n' $(echo $subnet | tr '.' ' '))
   
8.   mask_t=$((0xFFFFFFFF>>$mask))
   
9.   brd_t=$((subnet_t|mask_t))
   
10.   brd=$((($brd_t>>24)&0xff)).$((($brd_t>>16)&0xff)).$((($brd_t>>8)&0xff)).$(($brd_t&0xff))
    
11.   echo "${subnet}-${brd}"
    
12. done <a.txt

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