怎么用grep、awk、sed匹配出某个字符串，而不是字符串所在的整行

莫侠007

@Shell_HAT
如果bb是一正则表达式，$i该如何赋值比较bb为 $i~/2014[0-9]{1,2}/
[root@mysql-169 ~]# cat test1.txt
2014:10:54:07 20140512105355 20140512105355
2014:16:08:36 20140512160651 20140512160651
2014:17:00:35 20140512165939 20140512165939

取出 2014:10:54:07 20140512105355 20140512105355
源文件其实为：
175.20.26.19 - - [12/May/2014:10:54:07 +0800] POST /p/result?status=1&oid=2014051210535568540 HTTP/1.0 200 2965 9 ?status=1&oid=2014051210535568540 Mozilla/5.0 (Linux; U; Android 4.3; zh-cn; SM-N9002 Build/JSS15J) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30 0.009
27.149.237.36 - - [12/May/2014:16:08:36 +0800] GET /p/result?status=1&oid=2014051216065132350 HTTP/1.0 200 2884 9 ?status=1&oid=2014051216065132350 Mozilla/5.0 (Linux; U; Android 4.1.2; zh-cn; HUAWEI C8813Q Build/HuaweiC8813Q) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30 0.009
117.136.33.3 - - [12/May/2014:17:00:35 +0800] GET /p/result?status=1&oid=2014051216593980730 HTTP/1.0 200 2884 8 ?status=1&oid=2014051216593980730 Mozilla/5.0 (Linux; U; Android 4.2.2; zh-cn; Nexus 4 Build/JDQ39) AppleWebKit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30 0.008

Herowinter

回复 1# good_luck_68
grep本来就有-o选项，表示only match，只打印匹配的内容。

1. [masonzhu@rat122 zzz]$ grep -oP "(?<=^.)." i
   
2. b
   
3. e
   
4. 5
   
5. [masonzhu@rat122 zzz]$ grep -o "qwe" i
   
6. qwe

复制代码

jeffreyst

mark下，在下想到的，大神们说了，没想到到大神们也说了

莫侠007

回复 21# 莫侠007
参考 http://bbs.chinaunix.net/thread-1332348-1-1.html ，然后thnn 回答自己的问题了
[root@mysql-169 ~]# awk --re-interval -f awk.test test1.txt
2014:10:54:07 20140512105355 20140512105355
2014:16:08:36 20140512160651 20140512160651
2014:17:00:35 20140512165939 20140512165939
[root@mysql-169 ~]# cat awk.test
BEGIN {
i =0
}
{
x=$0
while (match(x, "2014[0-9]{1,10}" > 0) {
   printf substr(x, RSTART, RLENGTH) " "
   x = substr(x, RSTART+RLENGTH)
}
print ""
}

再一次谢谢 @Shell_HAT

   

daxuewuhen2014

grep -o qwe 1.txt

莫侠007

回复 25# daxuewuhen2014
grep -o xxx 1.txt 的话 匹配一次 换行一次 不符合要求吧