python调用shel命令&的问题

meto2009

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import os,commands
print "start...."
Return,Oput = commands.getstatusoutput('nohup python -m SimpleHTTPServer 8080 &') #运行到这儿不向后执行，如何规避
#os.system('nohup python -m SimpleHTTPServer 8080 &')
#os.popen('python -m SimpleHTTPServer 8080 &')
print ".....end"

wenhq

不加&可以不？

wenhq

commands.getstatusoutput(cmd)
Execute the string cmd in a shell with os.popen() and return a 2-tuple (status, output). cmd is actually run as { cmd ; } 2>&1, so that the returned output will contain output or error messages. A trailing newline is stripped from the output. The exit status for the command can be interpreted according to the rules for the C function wait().

看了下手册。

meto2009

谢谢，不加是可以的，

2>&1我的理解，在shell中这是错误输出复制一份到标准输出中，
'nohup python -m SimpleHTTPServer 8080 &'，我是想这一步在后台运行后，再执行一下步
现在用
os.system(),os.popen(),commands.getstatusoutput(cmd)都不知道如何实现

wenhq

python -m SimpleHTTPServer 8080  && disown -a && exit
一样的功能。