求问AWK里如何对一组数据的打印

mmwants

如文档如下:
------------------------------------------------
please check it

time 20130615
xxxxddddaaa
ccccaadee
cdcaaaaadd33333333333
fffffffffffffffffffffff
gggggggggggggggggggggggggggggggggggg

time 20130616
fggfdnrrrrrrrrrrrrrrrrrr
ghhhhhhhhhhhhhhhhhhhh
jjjjjjjjjjjjjjjjjjjjjjjjjjjjj
wwwwwwwwwwwwwwwwwww
httttttww

ccccRTRqqqqq
we are closed!
-----------------------------------------
请问如何只拿出 time 20130615的那段？
应该得到的print结果为：
time 20130615
xxxxddddaaa
ccccaadee
cdcaaaaadd33333333333
fffffffffffffffffffffff
gggggggggggggggggggggggggggggggggggg


使用AWK 如何拿出这一段的内容，请高手解答，给个思路啊。

dn833

1. awk 'BEGIN{RS="\n\n"}/time 20130615/' file
   

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seesea2517

回复 2# dn833


    高人。借花用用，删去四个字符

1. [seesea@UC ~]$ awk 'BEGIN{RS="\n\n"}/time 20130615/' file
   
2. time 20130615
   
3. xxxxddddaaa
   
4. ccccaadee
   
5. cdcaaaaadd33333333333
   
6. fffffffffffffffffffffff
   
7. gggggggggggggggggggggggggggggggggggg
   
8. [seesea@UC ~]$ awk 'BEGIN{RS=""}/time 20130615/' file   
   
9. time 20130615
   
10. xxxxddddaaa
    
11. ccccaadee
    
12. cdcaaaaadd33333333333
    
13. fffffffffffffffffffffff
    
14. gggggggggggggggggggggggggggggggggggg

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mmwants

dn833 发表于 2013-06-17 16:32

再问下高手，如果time之间没有空行怎么办？
--------------------------
please check it
time 20130615
xxxxddddaaa
ccccaadee
cdcaaaaadd33333333333
fffffffffffffffffffffff
gggggggggggggggggggggggggggggggggggg
time 20130616
fggfdnrrrrrrrrrrrrrrrrrr
ghhhhhhhhhhhhhhhhhhhh
jjjjjjjjjjjjjjjjjjjjjjjjjjjjj
wwwwwwwwwwwwwwwwwww
httttttww

ccccRTRqqqqq
we are closed!
---------------------

心若寒江雪

1. [root@localhost opt]# cat file
   
2. please check it
   
3. time 20130615
   
4. xxxxddddaaa
   
5. ccccaadee
   
6. cdcaaaaadd33333333333
   
7. fffffffffffffffffffffff
   
8. gggggggggggggggggggggggggggggggggggg
   
9. time 20130616
   
10. fggfdnrrrrrrrrrrrrrrrrrr
    
11. ghhhhhhhhhhhhhhhhhhhh
    
12. jjjjjjjjjjjjjjjjjjjjjjjjjjjjj
    
13. wwwwwwwwwwwwwwwwwww
    
14. httttttww
    
15. 
    
16. [root@localhost opt]# awk '{if($0 == "time 20130615"){a=1}else if($1 == "time" && $2 != "20130615"){a=0}}a' file
    
17. time 20130615
    
18. xxxxddddaaa
    
19. ccccaadee
    
20. cdcaaaaadd33333333333
    
21. fffffffffffffffffffffff
    
22. gggggggggggggggggggggggggggggggggggg

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WilliBhamlll

回复 4# mmwants


    awk '/time 20130615/{p=1}/time 20130616/{p=0}p' file
time 20130615
xxxxddddaaa
ccccaadee
cdcaaaaadd33333333333
fffffffffffffffffffffff
gggggggggggggggggggggggggggggggggggg

mmwants

心若寒江雪 发表于 2013-06-17 17:08

这也是一种思路啊，不错哦，保留了time字符，我看了下RS分割，如果用RS分割的话，time字符就没了

思路很好，谢谢啊。

mmwants

心若寒江雪 发表于 2013-06-17 17:08

这也是一种思路啊，不错哦，保留了time字符，我看了下RS分割，如果用RS分割的话，time字符就没了

思路很好，谢谢啊。

dn833

1. awk 'BEGIN{RS="time"}/20130615/{print RS" "$0}' file

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mmwants

dn833 发表于 2013-06-17 17:31

awk 'BEGIN{RS="time"}/20130615/{print RS" "$0}' file
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time 出现了，不知为不知啊，谢谢高手。