请问下面这段文本怎么过滤

smartlinux

文件中有多个记录,需要输出 type为false的记录, 只需要输出Name，Net，Gate

NAME: X1
Type: true
Net: 10.10.10.255/32
Alias-Address: 10.10.10.1
Flags: up

NAME: X1
Type: true
Net: 10.10.10.1/32
Flags: up

NAME: X1
Type: false
Net: 10.10.10.2/32
Gate: 192.168.153.102
Flags: up

关阴月飞

awk -vRS=''  '/false/{print $2,$6,$8}'

关阴月飞

小手一抖，发重了

zing840828

awk -vRS="" -vFS="\n" '/false/{for(i=1;i<=NF;i++){if($i~/NAME|Net|Gate/)print $i}}'

dn833

1. grep -C 2 "false" file|egrep -v "^$|false"

复制代码

linuxbrook

cat 10.txt |grep false -A4 -B1 | awk '{ if($1~/NAME|Net|Gate/) print $0 }'
NAME: X1
Net: 10.10.10.2/32
Gate: 192.168.153.102

cat 10.txt
NAME: X1
Type: true
Net: 10.10.10.255/32
Alias-Address: 10.10.10.1
Flags: up

NAME: X1
Type: true
Net: 10.10.10.1/32
Flags: up

NAME: X1
Type: false
Net: 10.10.10.2/32
Gate: 192.168.153.102
Flags: up

zxd_echo

awk  '/NAME/{s1=$2}/false/{s=s1}/Net/{s=s"\t"$2}/Gate/{ s=s"\t"$2;print s;}'

zxd_echo

#!/bin/awk -f

BEGIN{
        FS="\n"
        RS=""
}{
        if(index($0,"false")){
                print $1,$3,$4
   }
}

zhaopingzi

awk -vRS="" -vFS="\n" '$2~/false/{print $1"\n" $3"\n" $4"\n"}'  file
NAME: X1
Net: 10.10.10.2/32
Gate: 192.168.153.102