转义问题

zyj19871215

sed -r 's/[a-Z]+([^a-Z]+[a-Z]+)$/\1/' passwd_bak  删除每行的第二个单词
我 不想用-r，自己用转义
sed  's/\[a-Z]+\(\[^a-Z]+\[a-Z]+\)$/\1/' passwd_bak 为啥不可以呢？

jiaogeshahaone

\[^a-Z]+\[a-Z]+
转头不转尾？

li0924

1. cut -d" " -nf 1,3-

复制代码

jason680

回复 1# zyj19871215

You need to know what different between Extended and Basic regular expression
Note: Basic regular expression didn't support plus(+) sign for "One or more duplicates" function

http://www.grymoire.com/Unix/Regular.html#uh-12
   

zyj19871215

中括号就是转义头不转尾，小括号都需要转义回复 2# jiaogeshahaone


   

dn833

加号也得转

zyj19871215

我这里的加号是要匹配，不是加号，所以不用转义吧回复 6# dn833


   

dn833

随便你啦～～～just have a踹

zyj19871215

那你能给我一个正确的表达式嘛？回复 8# dn833


   

dn833

你能给两行文本，哥就敢说给你个表达式