本帖最后由 hgx126 于 2013-11-03 02:40 编辑
我有一gps文件如下:- A,021113,052743.159,3134.7623,N,10558.5112,E,014.0,+00.00,-10.41,+01.23;
- A,021113,052745.159,3134.7683,N,10558.5106,E,010.7,-00.61,-10.41,+00.00;
- A,021113,052745.159,3134.7683,N,10558.5106,E,010.7,-00.61,-10.41,+00.00;
- A,021113,052746.159,3134.7698,N,10558.5105,E,008.0,-01.84,-10.41,+01.23;
复制代码 拟将第四列数据减去0.1401,将第六列数据加上0.2311,并且该两列数据还是要保留4位小数。我用dos下的gawk处理,第4列只有2位,第六列只有1位,怎么也保留不了四位小数- gawk "BEGIN{FS=OFS=\",\"}{$4=$4-0.1401;$6=$6+0.2311;print $0}" gps.txt
复制代码 如何保留四位小数?。请教大家。
gawk.rar
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