批量修改日志文件名

kakaliu

要把connect.log.2014-02-14  变成connect.log.2014-02-15.。connect.log.2014-02-15 变成connect.log.2014-02-16 等等
connect.log.2014-03-01变成 connect.log.2014-03-02等等
依次内推 需注意2月28是月末 别弄成2月29了

rdcwayx

那你自己有没有试过呢？

yestreenstars

try:

1. mkdir tmp
   
2. for file in `ls connect.log.*`;do mv $file "tmp/${file%.*}."`date +%F -d "${file##*.}+1days"`;done
   
3. mv tmp/* .
   
4. rmdir tmp

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kakaliu

谢谢星辰，可以实现
但是其中的变量不是很明白
${file%.*}
以及${file##*.}

hhdzhu

回复 3# yestreenstars


    同问

yestreenstars

@kakaliu@hhdzhu

e.g.

1. $ file='connect.log.2014-2-28'
   
2. $ echo ${file%.*}
   
3. connect.log
   
4. $ echo ${file##*.}
   
5. 2014-2-28

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一个百分号或者井号表示懒惰匹配，两个表示贪婪匹配。
井号是从前往后匹配，百分号是从后往前匹配，并移除匹配到的内容。

man bash

       ${parameter#word}
       ${parameter##word}
              Remove matching prefix pattern.  The word is expanded to produce a pattern just as  in  pathname  expansion.   If  the  pattern
              matches  the  beginning of the value of parameter, then the result of the expansion is the expanded value of parameter with the
              shortest matching pattern (the ``#'' case) or the longest matching pattern (the ``##'' case) deleted.  If parameter is @ or  *,
              the  pattern  removal  operation  is applied to each positional parameter in turn, and the expansion is the resultant list.  If
              parameter is an array variable subscripted with @ or *, the pattern removal operation is applied to each member of the array in
              turn, and the expansion is the resultant list.

       ${parameter%word}
       ${parameter%%word}
              Remove  matching  suffix  pattern.   The  word  is expanded to produce a pattern just as in pathname expansion.  If the pattern
              matches a trailing portion of the expanded value of parameter, then the result of  the  expansion  is  the  expanded  value  of
              parameter  with  the  shortest matching pattern (the ``%'' case) or the longest matching pattern (the ``%%'' case) deleted.  If
              parameter is @ or *, the pattern removal operation is applied to each positional parameter in turn, and the  expansion  is  the
              resultant  list.   If  parameter is an array variable subscripted with @ or *, the pattern removal operation is applied to each
              member of the array in turn, and the expansion is the resultant list.

hhdzhu

回复 6# yestreenstars


    谢谢，怪不得搜正则表达式符号搜不到这些！

kakaliu

yestreenstars 发表于 2014-03-05 23:38
@kakaliu@hhdzhu

e.g.一个百分号或者井号表示懒惰匹配，两个表示贪婪匹配。

明白了 非常感谢！

Shell_HAT

@kakaliu
@hhdzhu
打开ABS，看看第120页。

Advanced Bash-Scripting Guide 3.9.1 中文版.pdf
http://bbs.chinaunix.net/thread-1610033-1-1.html