shell脚本中如何判断umount的成功/失败

wooin

shell脚本中应该如何表达这个意思呢？

if [ umount /mnt/disk ]; then
      echo "umount done!"
fi

谢谢！

ly5066113

回复 1# wooin

1. umount /mnt/disk && echo "umount done!"

复制代码

或者：

1. umount /mnt/disk
   
2. if [ $? -eq 0 ]; then
   
3.       echo "umount done!"
   
4. fi

复制代码

waker

if 　umount /mnt/disk
then
      echo "umount done!"
fi


umount /mnt/disk&&echo "umount done!"

haokoo

回复 3# waker


    umount 执行成功不是应该返回0嘛？  那if的判断应该不会执行吧？


测试了一下，判断通过...为毛

waker

回复 4# haokoo


    PAGER='less -iRsp "exit status"' man bash

liyunxiang12

回复 4# haokoo
shell中 0 也是true


   

haokoo

回复 5# waker

1. if list; then list; [ elif list; then list; ] ... [ else list; ] fi
   
2.               The if list is executed.  If its exit status is zero, the then list  is  executed.   Other-
   
3.               wise, each elif list is executed in turn, and if its exit status is zero, the corresponding
   
4.               then list is executed and the command completes.  Otherwise, the else list is executed,  if
   
5.               present.   The  exit  status is the exit status of the last command executed, or zero if no
   
6.               condition tested true.

复制代码

看到了，谢谢提醒。