截取字符串的问题

niccn20

During my childhood, think lucky money and new clothes are necessary for New Year, but as the advance of the age, will be more and more found that those things are optional; Junior high school, thought to have a crush on just means that the real growth, but over the past three years later, his writing of alumni in peace, suddenly found that isn't really grow up, it seems is not so important; Then in high school, think don't want to give vent to out your inner voice can be in the high school children of the feelings in a period, but was eventually infarction when graduation party in the throat, later again stood on the pitch he has sweat profusely, looked at his thrown a basketball hoops, suddenly found himself has already can't remember his appearance.

我想截取New Year到后面第一个and之间的内容，即这一段，该怎么做啊，然后判断这段内容里是否有but字符串。
求教。

yestreenstars

1. [root@localhost ~]# grep -Po 'New Year.*?and' i
   
2. New Year, but as the advance of the age, will be more and
   
3. [root@localhost ~]# grep -Po 'New Year.*?and' i | grep 'but'
   
4. New Year, but as the advance of the age, will be more and
   
5. [root@localhost ~]#

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niccn20

i是文件？另外问下   文件中有很多段落，这样也成立吗。

niccn20

New Year和第一个and可能在两段中。

yestreenstars

回复 3# niccn20

没错，i就是输入文件，你的意思是两个关键字可能不在同一行的情况也要匹配？
   

niccn20

对啊 就这意思 。其实简单点说就是一个文件里有很多行。
1 我想判断文件里有A和B字符串，并且A和B之间有C字符串。
2 文件里有A和C字符串就行。

seesea2517

回复 6# niccn20

在age后加了换行的文件测试如下：

1. [seesea@UC ~]$ sed -rn '1h; 1!H; $!b; g; s/.*(New Year.*and).*/\1/; p' file
   
2. New Year, but as the advance of the age,
   
3. will be more and

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seesea2517

回复 7# seesea2517

这个输出是否有but这个单词的判断结果：

1. [seesea@UC ~]$ sed -rn '1h; 1!H; $!b; g; s/.*(New Year.*and).*/\1/; /but/{s/.*/Have but/p; b}; s/.*/No but/p;' file
   
2. Have but

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seesea2517

回复 4# niccn20

awk 这个不担心有几次出现都可以匹配出来：

1. [seesea@UC ~]$ awk 'BEGIN {RS="New Year.*and"} {print RT}' file
   
2. New Year, but as the advance of the age,
   
3. will be more and

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