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guiguishell

如何用sed将下面文本中双引号内部的逗号换成空格
123,123,321,"1234,4567","123,456","321,345,567"

ly5066113

1. sed -r ':a;s/("[^"]+),([^"]+")/\1 \2/;ta' file

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zxy877298415

回复 1# guiguishell

echo '123,123,321,"1234,4567","123,456","321,345,567"' | sed -r 's/("),/\1 /g'
123,123,321,"1234,4567" "123,456" "321,345,567"
   

reyleon

1. awk 'BEGIN{RS="\"[^\"]+\"";ORS=""}{gsub(/,/,FS,RT);$0=$0""RT}1'

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祭出我大 awk

yestreenstars

1. awk -vRS='"' '!(NR%2){gsub(/,/," ")}{printf $0RT}'

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1. sed -r ':1;s/("[^"]+),([^"]+")/\1 \2/;t1'

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yestreenstars

回复 3# zxy877298415
你搞错了~{:2_172:}

   

zxy877298415

回复 6# yestreenstars

哦，是那样的双引号啊！


   

jgrlj322

-r  真的很好用。

MeRcy_PM

回复 8# jgrlj322
grep的-P更好使点。。。不知道啥时候能支持。
   

cjaizss

guiguishell 发表于 2014-06-30 16:06
如何用sed将下面文本中双引号内部的逗号换成空格
123,123,321,"1234,4567","123,456","321,345,567"

好久没写sed了

sed -nr ':a;s/(^|\n)([^"]*"[^\n"]*")($|[^\n])/\1\2\n\3/;ta;:b;s/,([^"]*"\n)/ \1/g;tb;s/\n//g;p'