请教各位，如何打印匹配行及其下一行，谢谢

blackold

Let's assume that you have a large log file
called log which contains thousands of lines
Justin Timberlake, Title
Another: Justin Timberlake, Title
545 Taylor Swift
The sed equivalent would be
723Mick Jagger, Title
610Lady Gaga


这种格式呢？

Herowinter

回复 11# blackold
。。。黑哥威武啊，我试了下我和星辰的代码，
545 Taylor Swift这一行都没正确输出。。。

1. [masonzhu@rat122 zzz]$ sed -n '/Title/,+1p' i
   
2. Justin Timberlake, Title
   
3. Another: Justin Timberlake, Title
   
4. 723Mick Jagger, Title
   
5. 610Lady Gaga
   
6. [masonzhu@rat122 zzz]$ sed -n '/Title/{N;p}' i
   
7. Justin Timberlake, Title
   
8. Another: Justin Timberlake, Title
   
9. 723Mick Jagger, Title
   
10. 610Lady Gaga
    
11. 
    
12. cat i
    
13. Let's assume that you have a large log file
    
14. called log which contains thousands of lines
    
15. Justin Timberlake, Title
    
16. Another: Justin Timberlake, Title
    
17. 545 Taylor Swift
    
18. The sed equivalent would be
    
19. 723Mick Jagger, Title
    
20. 610Lady Gaga

复制代码

Herowinter

回复 11# blackold

这样应该可以了吧。

1. sed -n '/Title/{:1;p;n;/Title/b1;p}' i
   
2. Justin Timberlake, Title
   
3. Another: Justin Timberlake, Title
   
4. 545 Taylor Swift
   
5. 723Mick Jagger, Title
   
6. 610Lady Gaga

复制代码