再请教一个关于自动代入变量的问题

tasteoftime_90

下午已经写过这样的了 不行啊
我的日志目录如下：
a1-1.log.1
a1-1.log.2
a1-1.log.3
a1-2.log.1
a1-2.log.2
a1-2.log.3
b1-1.log.1
b1-1.log.2
b1-1.log.3
b1-2.log.1
b1-2.log.2
b1-2.log.3

shell内容如下：
a1-1_log=$(ls -lt /try/a1-1.log.* |head -1 |awk '{print $9}')
a1-2_log=$(ls -lt /try/a1-2.log.* |head -1 |awk '{print $9}')
b1-1_log=$(ls -lt /try/b1-1.log.* |head -1 |awk '{print $9}')
b1-2_log=$(ls -lt /try/b1-2.log.* |head -1 |awk '{print $9}')
for file in a1-1.log a1-2_log b1-1_log b1-2_log; do
    test=$(grep -Po '(?<=xxoo )\d+' $file |tail -5 |awk '{print ;}')
    echo "$test" >> /try/try.txt
done

结果是：
test.sh: line 6: a1-1_log=: command not found
test.sh: line 7: a1-2_log=: command not found
test.sh: line 8: b1-1_log=: command not found
test.sh: line 9: b1-2_log=: command not found
grep: a1-1.log: 没有那个文件或目录
grep: a1-2_log: 没有那个文件或目录
grep: b1-1_log: 没有那个文件或目录
grep: b1-2_log: 没有那个文件或目录

另外，单独执行：
a1-1_log=$(ls -lt /try/a1-1.log.* |head -1 |awk '{print $9}')
grep -Po '(?<=xxoo )\d+' $file |tail -5 |awk '{print ;}'
就没问题，应该是for in循环的问题？
回复 10# Shell_HAT


   

Buring__

test=$(grep -Po '(?<=xxoo )\d+' <<<$file |tail -5 |awk '{print ;}')

Shell_HAT

回复 11# tasteoftime_90

1. a1_1_log=$(ls -1t /try/a1-1.log.* | head -1)
   
2. a1_2_log=$(ls -1t /try/a1-2.log.* | head -1)
   
3. b1_1_log=$(ls -1t /try/b1-1.log.* | head -1)
   
4. b1_2_log=$(ls -1t /try/b1-2.log.* | head -1)
   
5. for file in ${a1_1_log} ${a1_2_log} ${b1_1_log} ${b1_2_log}; do
   
6.     test=$(grep -Po '(?<=xxoo )\d+' $file | tail -5)
   
7.     echo "$test" >> /try/try.txt
   
8. done

复制代码

tasteoftime_90

我早上也刚刚发现问题 哈哈哈
想请教下为什么定义a1-1_log的时候不能使用“-”这一个符号
回复 13# Shell_HAT


   

jason680

回复 14# tasteoftime_90

说说你要什么功能...(看起来一个awk就能完成)

别再一直问 X-Y problem
just talk us what you want to do
http://bbs.chinaunix.net/forum.php?mod=viewthread&tid=4118053
   

Shell_HAT

回复 14# tasteoftime_90


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