[帮忙求助,谢谢]sed 截取或者删除第1行到最后一个关键字之间的行

chinasea100

例如我想删除下面文件111.txt中第1行到最后一次出现的关键字"starting"的所有行,保留最后一次出现的关键字"starting"的行
cat 111.txt;
syslogs1
syslogs2
stopping 1
a
a
starting 1
syslogs3
syslogs4
stopping 2
b
b
starting 2
syslogs5
syslogs6
stopping 3
c
c
starting 3
syslogs7
syslogs8
stopping 4
d
d
starting 4
syslogs9
syslogs10
syslogs11
syslogs7

想要得到的结果:
starting 4
syslogs9
syslogs10
syslogs11
syslogs7

reyleon

1. awk '{a[NR]=$0}/starting/{p=NR}END{for(i=p;i<=NR;i++)print a[i]}' file

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ly5066113

回复 1# chinasea100


try:

1. sed 'H;/starting/h;${g;p};d' 111.txt

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klainogn

1. sed -n 'H;/starting/{h};${g;p}' file

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li0924

1. awk 'NR==FNR{if($0 ~ /starting/)flag++;next}/starting/{flag--}! flag' file file

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lifayi2008

1. awk '{if($0~/starting/){delete a;a[i=1]=$0}else{a[++i]=$0}}END{for(j=1;j<=i;j++)print a[j]}' c.txt
   
2. sed -rn ':a;N;$!ba;s/.*(starting.*)/\1/p' c.txt

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jason680

回复 1# chinasea100

$ awk '{s=s"\n"$0}/^starting /{s=$0}END{print s}' FILE
starting 4
syslogs9
syslogs10
syslogs11
syslogs7

   

yestreenstars

1. sed -n 'H;/starting/h;${g;p}'

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chinasea100

回复 8# yestreenstars


    非常感谢,已经解决了

chinasea100

回复 2# reyleon


        非常感谢,已经解决了