[正则]借人气求一个python正则

ghostvic

要用Python从一个很长的串中提取一些字串（它们都以/jobs?viewJob=&jobId=开始，以%3Aprimary结束），

多谢了，各位

李满满

学生党:飘过~请楼主给详细点儿的文本方便测试~谢谢嗯

yinyuemi

re.findall((?<=right_text)(.*)?(?=left_text)),whole_text)

ghostvic

回复 2# 李满满


    :{"lix_header_lowercase":"control","EndorseDialogJS"unsaveJobUrl":"/job/consumer/savedItems/unsaveJobAjax?jobId=11339728&csrfToken=ajax%3A6032962507117593044&trk=vsrp_jobs_res_sec_act&trkInfo=VSRPsearchId%3A3779929881413714367824%2CVSRPtargetId%3A11339728%2CVSRPcmpt%3Aprimary"}]},"primaryAction":"view","saveJobUrl":"/job/consumer/savedItems/saveJobAjax?jobId=11339728&csrfToken=ajax%3A6032962507117593044&trk=vsrp_jobs_res_pri_act&trkInfo=VSRPsearchId%3A3779929881413714367824%2CVSRPtargetId%3A11339728%2CVSRPcmpt%3Aprimary","link_vie</script><script type="text/javascript">fs.embed("voltron_srp_main","

多谢了

ghostvic

回复 5# ghostvic


    好像没有目标数据...

看这个：
:{"lix_header_lowercase":"control","EndorseDialogJS":photo":"/jobs?viewJob=&jobId=11307997&trk=vsrp_jobs_res_photo&trkInfo=VSRPsearchId%3A3779929881413714367824%2CVSRPtargetId%3A11307997%2CVSRPcmpt%3Aprimary","fmt_job_recency":"3 days ago","postedDate":1413414469000,"companyLogoId":"/p/2/000/294/05d/0b9c5b8.png","companyId":406315,"fmt_postedDate":"Oct 15, 2014","link_biz_overview_5":"/company/406315?trk=vsrp_jobs_res_name&trkInfo=VSRPsearchId%3A3779929881413714367824%2CVSRPtargetId%3A11307997%2CVSRPcmpt%3Aprimary","link_viewJob":"/jobs?viewJob=&jobId=11307997&trk=vsrp_jobs_res_name&trkInfo=VSRPsearchId%3A3779929881413714367824%2CVSRPtargetId%3A11307997%2CVSRPcmpt%3Aprimary","isApplied":false,"id":11307997,"link_voltron_job_search_5":"/vsearch/j?rsid=3779929881413714367824&pivotType=sim&pid=11307997&trk=vsrp_jobs_res_sim&trkInfo=VSRPsearchId%3A37799298</script><script type="text/javascript">fs.embed("voltron_srp_main","

ghostvic

回复 4# yinyuemi


   我试了下，不知道为啥不行，我啥地方写错了么？
foundURL = re.findall(r'(?<=/jobs?viewJob)(.*)?(?=%3Aprimary)',data)

谢谢

ghostvic

ghostvic 发表于 2014-10-20 10:01
回复 4# yinyuemi

自己搞出来了，
foundURL = re.findall(r'\/jobs\?viewJob.*?%3Aprimary',data)

但是用(?<=right_text)(.*)?(?=left_text) 总报错

欧阳西风

回复 7# ghostvic


    这个可以 将第二个?使用反斜线转义，把第三个?放到括号里面 foundURL = re.findall(r'(?<=/jobs\?viewJob)(.*?)(?=%3Aprimary)',data)

另外 这个正则匹配到的字符串是不包含/jobs?viewJob以及%3Aprimary头尾的，只会获得头尾之间的字符串。

圣西罗门柱

1. re.findall(r'\/jobs\?viewJob=(.*)%3Aprimary',url)

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