如何抽取含有6个以上指定字符的行

chenjiali1

大家好，我的文件如下：
XM:Z:..H.......X.zx........XH.H..........h..Xh...xh......HH....Hh.Z...H..........h.H..h.......X......h...X
XM:Z:H.....H.......X.zx........XH.H..........h..Xh...xh......HH....Hh.Z...H..........h.H..h.......X......h
XM:Z:.......x....h......x..x.......hh.x......hh.z..........h....h......x.......h.h.....hxz....x...........
XM:Z:....h.....h....x...hx...x...........x....h......x..x.......hh.x......hh.z..........h....h......x.....
XM:Z:.....hh....h...h.h..x.....h...h.h...hh....hhhx..hh.h.....x......x........hh.hhh........x......x..x...
XM:Z:.....h...h.h...hh....hhhx..hh.h.....x......x........hh.hhh........x......x..x.....h...hx.....h.......


如果该行中除了XM:Z，在Z：后面大写的X，H和Z三个字母出现的总次数大于6，则该行删掉，只输出X，H和Z总和小于等于6的行，结果应该是除1,2行之外的其它行，请问如何实现。XM:Z 中的X和Z不能算哈！

还有我想抽取含有大写字母X，H和Z的行，如何让它不匹配XM:Z 这几个字符呢？

谢谢大家！

wiliiwin

1. # awk  '{T=substr($0,6);split(T,a,"");for(j in a){if(a[j]~/[HXZ]/){i++}};if(i<=6){print $0};i=0}' 29.txt
   
2. XM:Z:.......x....h......x..x.......hh.x......hh.z..........h....h......x.......h.h.....hxz....x...........
   
3. XM:Z:....h.....h....x...hx...x...........x....h......x..x.......hh.x......hh.z..........h....h......x.....
   
4. XM:Z:.....hh....h...h.h..x.....h...h.h...hh....hhhx..hh.h.....x......x........hh.hhh........x......x..x...
   
5. XM:Z:.....h...h.h...hh....hhhx..hh.h.....x......x........hh.hhh........x......x..x.....h...hx.....h.......

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tasteoftime_90

1. awk -F[XHZ] '{if(NF-3<'6'){print ;}}'

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妈蛋 回错贴了回复 1# chenjiali1


   

love_shift

回复 3# tasteoftime_90

思路不错~
   

chenjiali1

回复 2# wiliiwin


    好像不对呢？我想把除了1,2行之外的全输出来

wiliiwin

回复 5# chenjiali1

恩刚才没有看清楚题  现在ok了


   

zxy877298415

回复 1# chenjiali1
awk -F ''  '{t=0;for (i=5;i<=NF;i++) {if ($i~/[HXZ]/) t++}}(t<6) ' FILE


   

ly5066113

回复 1# chenjiali1


1.

1. awk '{v=substr($0,5)}gsub(/[XHZ]/,"",v)<=6' file

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2.

1. grep -P '^XM:Z(?=.*X)(?=.*H)(?=.*Z)' file

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bulletmarquis

回复 8# ly5066113


    这个思路牛X。。。学习~~

yestreenstars

1. awk 'gsub(/[XHZ]/,"&")<8'

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