求教list的remove方法

amandaysu

1
>>> c=['s1','s2']
>>> c
['s1', 's2']
>>> c.remove('s1')
>>> c
['s2']

2
>>> print ['s1','s2'].remove('s2')

求教一下1和2的区别在哪里，为什么我用第二种方式得到的是None？

bskay

你做的只是相当于下面这样的



1
>>> c=['s1','s2']
>>> c
['s1', 's2']
>>> c.remove('s1')

2
>>> print ['s1','s2'].remove('s2')

amandaysu

没明白
回复 2# bskay


   

HH106

1. Syntax
   
2. Following is the syntax for remove() method:
   
3. 
   
4. list.remove(obj)
   
5. Parameters
   
6. obj -- This is the object to be removed from the list.
   
7. 
   
8. Return Value
   
9. This method does not return any value but removes the given object from the list.

复制代码

amandaysu

thanks回复 4# HH106


   

reyleon

列表对象的方法都是在 "原处"  进行修改的!

szerr

['s1','s2'].remove('s2') 没有返回值，所以没输出。

jixuuse

Python 2.7.6 (default, Nov 10 2013, 19:24:24) [MSC v.1500 64 bit (AMD64)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> x=['s1','s2']
>>> x
['s1', 's2']
>>> x.remove('s2')
>>> x
['s1']
>>>