请教字符串处理问题

Unixell

请教一下，我想把下面的文本：

1. 4 [192.168.9.11:5452:153, 192.168.9.11:5000:77, 192.168.9.11:4888:154]
   
2. 3 [192.168.9.12:5452:171, 192.168.9.11:5000:85]
   
3. 2 [192.168.9.13:5452:153, 192.168.9.11:5000:77, 192.168.9.11:4888:154]
   
4. 1 [192.168.9.14:5452:96, 192.168.9.11:5000:96, 192.168.9.11:4888:192]

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处理成这样的格式：

1. 4 [192.168.9.11:5452:PORT, 192.168.9.11:5000:PORT, 192.168.9.11:4888:PORT]
   
2. 3 [192.168.9.12:5452:PORT, 192.168.9.11:5000:PORT]
   
3. 2 [192.168.9.13:5452:PORT, 192.168.9.11:5000:PORT, 192.168.9.11:4888:PORT]
   
4. 1 [192.168.9.14:5452:PORT, 192.168.9.11:5000:PORT, 192.168.9.11:4888:PORT]

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我尝试用sed解决，没搞定，请各位大侠支招，多谢

zxy877298415

1. awk -F '[0-9]*,|[0-9]*]' '{for (i=1;i<NF;i++) {if(i==NF-1) {$i=$i"PORT]"} else {$i=$i"PORT"}}}1' file
   
2. 4 [192.168.9.11:5452:PORT  192.168.9.11:5000:PORT  192.168.9.11:4888:PORT]
   
3. 3 [192.168.9.12:5452:PORT  192.168.9.11:5000:PORT]
   
4. 2 [192.168.9.13:5452:PORT  192.168.9.11:5000:PORT  192.168.9.11:4888:PORT]
   
5. 1 [192.168.9.14:5452:PORT  192.168.9.11:5000:PORT  192.168.9.11:4888:PORT]

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回复 1# Unixell


   

liion631818

回复 1# Unixell

1. px@ubuntu:~$ echo '4 [192.168.9.11:5452:153, 192.168.9.11:5000:77, 192.168.9.11:4888:154]' | sed -r 's/:[0-9]+([],])/:PORT\1/g'
   
2. 4 [192.168.9.11:5452:PORT, 192.168.9.11:5000:PORT, 192.168.9.11:4888:PORT]

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关阴月飞

1. awk '{gsub(/:[0-9]+,/,":PORT");gsub(/:[0-9]+]/,":PORT]")}1' urfile

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冰谛

awk '{gsub(":*[,\\]]",":PORT,",$0)}1'   file  |  awk  -F ":" '{OFS=":";$NF="PORT]"}1'

LikeLx

1. awk '{print gensub(/(:)[0-9]+(,|])/,"\\1PORT\\2","g",$0)}'

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mvplove123

awk --re-interval -F"," '{for(i=1;i<=NF;i++){gsub(/:[0-9]{2,3}]?$/,"ORT",$i);printf $i;if(i==NF){printf "\n"}}}' a

tasteoftime_90

1. sed -r 's/[0-9]+((,|]))/PORT\1/g'

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回复 1# Unixell


   

zsszss0000

sed -r 's/:[0-9]+([],])/: PORT\1/g'

高手能不能详细的解答一下这句？回复 3# liion631818


   

baochenggood

好屌，受教了  回复 4# 关阴月飞