python字典遍历

constant_zyh188

现在有系统api接口
通过浏览器打开以后为下面数据：样例
[ { "appList": [ "AA", "BB", "CC" ], "assetSerialNumber": "C1-ST-6565", "devAdminIP": "1.1.1.1", "devAdminPort": "22", "devCode": "010061371", "devDepartment": "服务", "devName": "CCC-NK-1-371", "devStatus": "CLOSE", "nodeType": "CCABROAD", "serialNum": "PR1310D2007070041" }, { "appList": [ "AA", "BB", "OS", "DD" ], "assetSerialNumber": "C1-ST-6837", "devAdminIP": "2.2.2.2", "devAdminPort": "22", "devCode": "010002372", "devDepartment": "服务", "devName": "aaa-ccK-1-372", "devStatus": "CLOSE", "nodeType": "CCABROAD", "serialNum": "PR1310D2007070155" }


现在想通过python，当执行不一样的参数时，也就是不一样的健，得到不一样的值

例如：
devAdminIP:  会得出上面api内容里所有的ip地址。

constant_zyh188

通过 urlopen打开 赋值给以后，print显示
    {
    "appList":     [
      "AA",
      "BB",
      "CC",
      "DD"
    ],
    "assetSerialNumber": "",
    "devAdminIP": "1.1.1.1",
    "devAdminPort": "22",
    "devCode": "96000713T7",
    "devDepartment": "GGG",
    "devName": "CCC-LD-1-3T7",
    "devStatus": "OPEN",
    "nodeType": "MAINLAND",
    "serialNum": "3SHJD3X_3"
  },
    {
    "appList":     [
      "AA",
      "BB",
      "CC",
      "DD"
    ],
    "assetSerialNumber": "",
    "devAdminIP": "2.2.2.2",
    "devAdminPort": "22",
    "devCode": "96000713T7",
    "devDepartment": "GGG",
    "devName": "CCC-LD-1-3T8",
    "devStatus": "OPEN",
    "nodeType": "MAINLAND",
    "serialNum": "3SHJD3X_4"
  },
.........
.........

goofool

现在不就已经是这样了吗

Linux_manne

就是对 json 的操作啊 典型的字典操作吧

anthonyfeng

基本是这样：
        page = urllib.urlopen(url)
        html = page.read()
        dict = json.loads(html)

constant_zyh188

对，我是想建立各种方法，然后提取各个项的值，但是这个文件下来有很多个字典分组，我怎么遍历？

substr函数

基本是这样

howge

已经是json格式了，大锅您还要怎么操作？ help下