请教一个用win32库写deamon的问题

lion_lol

我写了一个wmi的监控想放到后台运行,用win32库的一个模板,但是在运行的时候可以安装服务,但是却启动不了服务
cmd 执行 win_deamon.py install 没有问题,执行win_deamon.py start就不行了,有人知道怎么解决吗?
执行win_deamon.py debug 也没有问题
代码是如下 Powershell是我写的模块命名
#!/usr/bin/python
# -*- coding: utf-8 -*-
import win32serviceutil
import win32service
import win32event
import powershell
class SmallestPythonService(win32serviceutil.ServiceFramework):
    _svc_name_ = "Disk Monitor Service"
    _svc_display_name_ = "The smallest possible Python Service"
    def __init__(self, args):
        self.threads = []
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
    def SvcStop(self):
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        win32event.SetEvent(self.hWaitStop)
    def SvcDoRun(self):
        #This is my program !
        powershell.demo()
        self.threads = []
        win32event.WaitForSingleObject(self.hWaitStop, win32event.INFINITE)
if __name__=='__main__':
    win32serviceutil.HandleCommandLine(SmallestPythonService)

lion_lol

最终自己找到了解决方案...
把python的path添加到系统的环境变量就可以了,原文如下
What you need to do is to add the Python27 to SYSTEM PATH, and not to USER PATH, since as a default the python service will get installed as a 'LocalSystem' and so when it attempts to start it uses the SYSTEM PATH variable - that's why you can run it from the command prompt, your USER PATH is right.