BeautifulSoup如何查找class标签

cc7756789w

<a href="aaaas"><img src="saaa"/></a>
<a class="url" href="saasa">那个分享第二份职业，两个月...</a>
<a href="aaaaa"><img src="aaaaa"></a>
<a class="url" href="aaaaa">兼职一：这是一个在手机上赚...</a>
<a href="saa">缁欐垜鍏虫敞鐨勪汉鍐欎俊</a>
<a href="saaaat">鍘绘垜鍏虫敞鐨勪汉鍒楄〃</a>

我想匹配出class="url"标签

1. from bs4 import BeautifulSoup
   
2. import string, re
   
3. 
   
4. f = open('dy.html', 'r')
   
5. html = f.readlines()
   
6. soup = BeautifulSoup(string.join(html, ''))
   
7. for link in soup.find_all('a'):
   
8.     print link.find(class_='url')
   
9.     print link.find(attrs={'class','url'})

复制代码

都显示None

cc7756789w

问题解决了，得这么搞

1. 
   
2. soup = BeautifulSoup(self.response.read())
   
3. tag = soup.find_all('span', attrs={'class':'from'})
   
4. tag2 =  soup.find_all('a', attrs={'class':'url'})
   

复制代码

boatinwind

回复 2# cc7756789w

我也刚学，找class感觉最爽了。嗖嗖快


# -*- coding: UTF-8 -*-

from bs4 import BeautifulSoup

the_html="""
<a href="aaaas"><img src="saaa"/></a>
<a class="url" href="saasa">那个分享第二份职业，两个月...</a>
<a href="aaaaa"><img src="aaaaa"></a>
<a class="url" href="aaaaa">兼职一：这是一个在手机上赚...</a>
<a href="saa">缁欐垜鍏虫敞鐨勪汉鍐欎俊</a>
<a href="saaaat">鍘绘垜鍏虫敞鐨勪汉鍒楄〃</a>
"""

soup=BeautifulSoup(the_html)

for one in soup(class_="url"):
    print one