Python eval（）函数报错

jack_yanf

#!/usr/bin/env  python

def leastCoin(coinNum):
      coin = [25,10,5,1]
      coinN = []
      for item in coin:
           coinN.append(eval(coinNum) / item)
           coinNum = eval(coinNum)% item
      return coinN

if __name__ == "__main__":
    coin = raw_input('Enter your coin num,Please!')
    coinN = leastCoin(coin)
    print 'The least coin for %d is 25:%d,10:%d,5:%d,1:%d' %(coin,coinN[0],coinN[1],coinN[2],coinN[3])
大神们给看看，运行的时候报错

本人刚刚接触python不久，问的问题可能过于简单，不过希望各位大神能够耐心的帮我解惑下，万分感谢。

haooooaaa

你这个直接用 int  就可以了，

eval（） 括号里面要表达式或者是变量名字符

比如  eval(2+3)

jack_yanf

回复 2# haooooaaa
用了int 好像不行，如果要输入float类型的也不行的吧，  eval()里面也是表达式呀，是取余和取摸呀


   

Linux_manne

完全不明白你要干嘛....

substr函数

好像行的吧

1. Enter your coin num,Please! 56
   
2. The least coin for 56 is
   
3. 
   
4. [(25, 2), (10, 0), (5, 1), (1, 1)]

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1. def leastCoin(coinNum):
   
2.     coin = [25, 10, 5, 1]
   
3.     coinN = []
   
4.     for item in coin:
   
5.         coinN.append(coinNum / item)
   
6.         coinNum = coinNum % item
   
7.     return zip(coin, coinN)
   
8. 
   
9. 
   
10. coin = input('Enter your coin num,Please! ')
    
11. result = leastCoin(coin)
    
12. 
    
13. print 'The least coin for %d is\n' % coin
    
14. print result

复制代码