根据节点名称修改节点的值

路人呵呵

xml文件内容:
<content>
   <param-name>ADC</param-name>
   <param-value>EZ</param-value>
</content>
<content>
   <param-name>AP</param-name>
   <param-value>赏金猎人</param-value>
</content>
<content>
   <param-name>坦克</param-name>
   <param-value>盖伦</param-value>
</content>
<content>
   <param-name>辅助</param-name>
   <param-value>琴女</param-value>
</content>

求如何用sed实现根据param-name提供的值去修改对应param-value里面的值?
比如我写的脚本接收两个参数.分别是param-name和param-value.
当param-name值是: 辅助;param-value:风女.
通过这个脚本可以把
<content>
   <param-name>辅助</param-name>
   <param-value>琴女</param-value>
</content>
修改成
<content>
   <param-name>辅助</param-name>
   <param-value>风女</param-value>
</content>

求大神指点?

songyc_2015

回复 1# 路人呵呵

1. a="辅助"
   
2. b="风女"
   
3. sed -r '/<content>/{:a;N;/<\/content>/!ba;s#^(.*name>'${a}'</.*>)[^<]+(</param-value.*)$#\1'${b}'\2#;}' b.txt

复制代码

songyc_2015

回复 1# 路人呵呵

1. a="辅助"
   
2. b="风女"
   
3. awk -vRS='</?content>' -va=$a -vb=$b 'NF>1&&$0~a{$0=gensub(/>[^>]+<\//,">"b"</",2)}{ORS=RT}1' b.txt

复制代码