awk 字符串处理

logo111

,,,,,,,,,,answer,,test,

想要得到 answer,test
去除所有多余的,
应该如何处理。
麻烦各位帮忙看一下。

谢谢。

Herowinter

回复 1# logo111


    需求是要取后两列还是answer test可以作为关键字?

jason680

回复 1# logo111

$ echo ',,,,,,,,,,answer,,test,' | awk '{gsub(/^,+|,+$/,"");gsub(",+",",")}1'
answer,test

$ echo ',,,,,,,,,,answer,,test,' | sed -r 's/^,+|,+$//g;s/,+/,/g'
answer,test

logo111

谢谢！
回复 3# jason680


   

songyc_2015

回复 1# logo111

1. echo ',,,,,,,,,,answer,,test,' | awk -vRS="," 'NF{s=s?s","$0:$0}END{print s}'

复制代码

stupid_lee

1. awk -F, '{for(i=1;i<=NF;i++)if($i ~ /answer|test/)s=s?s","$i:$i}END{print s}'

复制代码

1. sed -r 's/[^(answer)(test)]+/,/g;s/^,|,$//g'

复制代码

stupid_lee

回复 2# Herowinter

英雄哥还没学会抢答