求解取ifconfig命令中的ip地址的若干写法。。。。

驱魔圣手

grep,sed,awk各种处理方式，求解答。。。。

Shell_HAT

1. ifconfig | sed -n '/eth0/{N;s/.*inet addr://;s/ .*//p}'
   
2. ifconfig | awk '/eth0/{getline;gsub(/addr:/,"",$2);print $2}'
   
3. ifconfig | awk -F"[ \t:]+" -vdev=eth0 '$2=="Link"{d=$1==dev?1:0}d&&/inet addr:/{print $4}'
   
4. ifconfig eth0 | sed '/inet addr/!d; s/.*inet addr://; s/ .*//'
   
5. ifconfig eth0 | awk -F '[: ]+' '/inet addr/{print $4}'
   
6. ifconfig eth0 | awk '/inet addr/{gsub(/addr:/,"",$2);print $2}'
   
7. ifconfig eth0 | awk -vRS='inet addr:' 'NR!=1{print $1}'
   
8. ifconfig eth0 | grep -Po '(?<=inet addr:)\S+'
   
9. ip r | awk 'NR==1{print $NF}'

复制代码

jason680

回复 1# 驱魔圣手

What You Want Is What You Code(WYWIWYC)

$ ifconfig eth3
eth3      Link encap:Ethernet  HWaddr 08:00:12:34:56:78  
          inet addr:10.0.222.15  Bcast:10.0.222.255  Mask:255.255.255.0
          inet6 addr: fe80::a00:12ff:fe34:5678/64 Scope:Link
          ...

$ ifconfig eth3 | grep -oP "HWaddr \K\S+"
08:00:12:34:56:78

$ ifconfig eth3 | grep -oP "inet addr:\K\S+"
10.0.222.15

$ ifconfig eth3 | grep -oP "inet6 addr: \K\S+"
fe80::a00:12ff:fe34:5678/64

$ ifconfig eth3 | grep -oP "inet6 addr: \K[^\/]+"
fe80::a00:12ff:fe34:5678

$ ifconfig eth3 | awk 'match($0,/HWaddr ([^ ]+)/,a){print a[1]}'
08:00:12:34:56:78

$ ifconfig eth3 | awk 'match($0,/inet addr:([^ ]+)/,a){print a[1]}'
10.0.222.15

$ ifconfig eth3 | awk 'match($0,/inet6 addr: ([^ ]+)/,a){print a[1]}'
fe80::a00:12ff:fe34:5678/64

$ ifconfig eth3 | awk 'match($0,/inet6 addr: ([^\/]+)/,a){print a[1]}'
fe80::a00:12ff:fe34:5678

驱魔圣手

多谢。。。还是你写的平民看的懂。。。。回复 2# Shell_HAT


   

huazai0715

大神，膜拜中回复 3# jason680