read 怎样写输入的内容为日期的格式？

johnson0418

user1> more aa
read -p "please input Date:" date
echo -e "\n"
echo "$date" > date.temp

date的格式为日期，如20160101（年月日），如果格式不对，重新输入；如果为空，保持原有的设置，要怎么写？

johnson0418

elu_ligao

1. while read -p "please input Date:" data
   
2. do
   
3.     [[ "x"$data == "x" ]] && break
   
4.     [[ ! $data =~ ^[0-9]{8}$ ]] && continue
   
5.     year=${data:0:4}
   
6.     monday=${data:4:4}
   
7.     [[ ! $data =~ (([0-9]{2})(0[48]|[2468][048]|[13579][26])|(0[48]|[2468][048]|[13579][26])00)0229 ]] && continue || break
   
8.     [[ ! $monday =~ (0[13578]|1[02])(0[1-9]|[12][0-9]|3[01]) || ! $monday =~ (0[469]|11)(0[1-9]|[12][0-9]|30) || ! $monday =~ 02(0[1-9]|[1][0-9]|2[0-8]) ]] && continue
   
9.     break
   
10. done
    
11. echo "$data"

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johnson0418

回复 3# elu_ligao


    谢谢你的回复。测试一下，有点问题，不知道要怎么修改？

1. [root]# cat cc
   
2. #!/bin/bash
   
3. 
   
4. while read -p "please input Date:" data
   
5. do
   
6.     [[ "x"$data == "x" ]] && break
   
7.     [[ ! $data =~ ^[0-9]{8}$ ]] && continue
   
8.     year=${data:0:4}
   
9.     monday=${data:4:4}
   
10.     [[ ! $data =~ (([0-9]{2})(0[48]|[2468][048]|[13579][26])|(0[48]|[2468][048]|[13579][26])00)0229 ]] && continue || break
    
11.     [[ ! $monday =~ (0[13578]|1[02])(0[1-9]|[12][0-9]|3[01]) || ! $monday =~ (0[469]|11)(0[1-9]|[12][0-9]|30) || ! $monday =~ 02(0[1-9]|[1][0-9]|2[0-8]) ]] && continue
    
12.     break
    
13. done
    
14. echo "$data"
    
15. [root]# ./cc
    
16. ./cc: line 6: conditional binary operator expected
    
17. ./cc: line 6: syntax error near `=~'
    
18. ./cc: line 6: `    [[ ! $data =~ ^[0-9]{8}$ ]] && continue'
    
19. [root]#
    
20. 
    

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elu_ligao

回复 4# johnson0418


    我自己测了下， 逻辑有问题

1. while read -p "please input Date:" data
   
2. do
   
3.     [[ "x"$data == "x" ]] && break
   
4.     [[ ! $data =~ ^[0-9]{8}$ ]] && continue
   
5.     year=${data:0:4}
   
6.     monday=${data:4:4}
   
7.     [[ $data =~ (([0-9]{2})(0[48]|[2468][048]|[13579][26])|(0[48]|[2468][048]|[13579][26])00)0229 ]] && break
   
8.     [[ $monday =~ (0[13578]|1[02])(0[1-9]|[12][0-9]|3[01]) || $monday =~ (0[469]|11)(0[1-9]|[12][0-9]|30) || $monday =~ 02(0[1-9]|[1][0-9]|2[0-8]) ]] && break
   
9. done
   
10. echo "$data"
    
11. 
    
12. sh data.sh
    
13. please input Date:20120230
    
14. please input Date:20000229
    
15. 20000229

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你的是bash吗？    =~ 是匹配呀， 怎么语法错误呢

我是一隻羊

1. #!/bin/bash
   
2. 
   
3. data=$1
   
4. 
   
5. date -d $data &>/dev/null && [ ${#data} -eq 8 ] \
   
6.         && echo "right format" \
   
7.         || echo "wrong format"

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1. sh test.sh 20150101
   
2. right format
   
3. sh test.sh dasfafadsfad
   
4. wrong format

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johnson0418

回复 5# elu_ligao


    是bash。但我的还是不行运行，提示错误！

LikeLx

1. 2016-2-2

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回复 6# 我是一隻羊


   

hz_oracle

#/bin/bash
#
until [ "$test" == 0 ]
do
read -p "please input Date: " d
date -d "$d" "+%s"
test=`echo $?`
done
echo "$d"

johnson0418

回复 9# hz_oracle

运行结果如下。
users > ./yy
please input Date: 20160101
1451577600
20160101

date -d "$d" "+%s" 是什么意思？