想打印匹配行到不是空格为首的行之间的内容

General_715

#cat a.txt
a1 =

  (DESCRIPTION =

    (ADDRESS = (PROTOCOL = TCP)(HOST = oracle)(PORT = 1000))

    (CONNECT_DATA =

      (SERVER = aaa)

      (SERVICE_NAME = aaa)

a2 =

  (DESCRIPTION =

    (ADDRESS = (PROTOCOL = TCP)(HOST = bbb-vip)(PORT = 1000))

    (CONNECT_DATA =

      (SERVER = ccc)

      (SERVICE_NAME = bbb)

a3 =

  (DESCRIPTION =

    (ADDRESS = (PROTOCOL = TCP)(HOST = ccc-vip)(PORT = 1000))

    (CONNECT_DATA =

      (SERVER = ccc)

      (SID = ccc)
之前会有一个列表 列出a1 a2 a3
如果输入a1 就打印从a1开始 到a2的上一行(就是打印到不以空格为首的上一行)
请问怎么写能打印出来

haooooaaa

1. awk -vRS='a[0-9]+ *= *\n' -vk=3 'RT~"^a"k" "{getline;printf $0}'

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1. awk -vk=3 '/^[^ ]+/{m=0}$0~"^a"k" "{m=1;next}m'

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mswsg

顶下，厉害，学习！
楼主的意思是？比如输入a1，则打a1的内容到屏幕（shell）？
还是文本的提取？回复 2# haooooaaa

1. #!/usr/bin/env python
   
2. # -*- coding: utf-8 -*-
   
3. b = ['a1', 'a2']
   
4. with open('1.txt', 'r') as f:
   
5.     a = []
   
6.     lines = f.readlines()
   
7.     print(lines[0])
   
8.     for x in lines:
   
9.         if x.startswith('a'):
   
10.             a.extend([x.strip().split()[0], lines.index(x),])
    
11.     for i in b[:-1]:
    
12.         if i in a:
    
13.             c = a.index(i)
    
14.             print ''.join(lines[a[c+1]:a[c+3]])
    
15.     if b[-1] == a[-2]:
    
16.         print ''.join(lines[a[int(a.index(b[-1]) + 1)]:])
    
17.     else:
    
18.         print ''.join(lines[a[int(a.index(b[-1])) + 1]:a[int(a.index(b[-1])) + 3]])
    

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jason680

回复 1# General_715


$ awk 'BEGIN{while(getline < "a.txt"){if(/^[^ \t]+/){k=$1;printf k" ";d[++c]=k};a[k]=a[k]$0"\n"}printf "\ninput: ";getline;print a[$1]}'
a1 a2 a3
input: a1
a1 =
  (DESCRIPTION =
    ...
      (SERVICE_NAME = aaa)


$ awk 'BEGIN{while(getline < "a.txt"){if(/^[^ \t]+/){k=$1;printf k" ";d[++c]=k};a[k]=a[k]$0"\n"}printf "\ninput: ";getline;print a[$1]}'
a1 a2 a3
input: a2
a2 =
  (DESCRIPTION =
    ...
      (SERVICE_NAME = bbb)


$ cat a.txt
a1 =
  (DESCRIPTION =
    ...
      (SERVICE_NAME = aaa)

a2 =
  (DESCRIPTION =
    ...
      (SERVICE_NAME = bbb)

a3 =
  (DESCRIPTION =
    ...
      (SID = ccc)

   

moperyblue

1. #如果每段行数一样
   
2. val=a3
   
3. grep "$val" -A10 a.txt
   
4. 
   
5. #
   
6. val=a3
   
7. sed  '/'"$val"'/{:a;N;/\na/!{$!ba};s/\n\na.*//;b};d' a.txt

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elu_ligao

1. awk -vs="a2" 'f&&/^[^ \t]+/{f=!f}$0~s" ="{f=1}f'
   

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lll1985911

sed -r -n '/^a1/,/^a/{/^a/d;p}' FILE

liion631818

回复 1# General_715

1. sed -nr '/^[^ ]/{x;/^a3/p;b};${x;/^a3/p;b};H'

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sunzhiguolu

1. perl -ne '{m/\A\S/?($k=$_):push(@{$h{$k}},$_)}END{$,="\n";print "Enter a key:";chomp($k=<STDIN>);for(keys %h){print $_,@{$h{$_}} if(m/$k/)}}' f

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287380917

你这个应该是数据库的监听配置文件吧。
你试试这个脚本：

1. if [ $# -gt 1 ];then
   
2.         echo "参数过多!"
   
3.         exit 1
   
4. fi
   
5. 
   
6. #输出文件中包含多少个server_name
   
7. #将server_name附近加上#号
   
8. sed  's/\(^[^ ]*\)\(.*\)/#\1#\2/g;s/##//g' a.txt >tempfile
   
9. #获取各个server_name
   
10. servers=`awk 'BEGIN{RS="#"}NR>1{print $0;getline}' tempfile`
    
11. 
    
12. if [ $# -eq 0 ];then
    
13. #打印server列表
    
14. echo "server_name列表如下：`echo $servers`；如需查看对应列表，请使用:$0 server_name方式查看"
    
15. rm tempfile
    
16. exit 0
    
17. fi
    
18. 
    
19. name=$1
    
20. #从tempfile中获取对应server_name的配置信息
    
21. awk -v name1=$name 'BEGIN{RS="#"}NR>1{if($0 == name1){printf $0;getline;print $0;exit}}' tempfile > resultfile
    
22. rm tempfile

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输入的服务名不对就查不到信息，懒得在脚本里面做判断了