Shell 脚本编写

Jason_0316

回复 20# sunzhiguolu


    可以了，非常感谢！

hz_oracle

#!/bin/bash
#
time=`awk '!a[$3]++{print $3}' bu.txt`
for i in $time
do
key=`grep "$i" bu.txt | awk -F"BU|-" '{print $2}' | sort -n | sed -n '$p'`
k=`grep "$i" bu.txt |grep "BU$key" | sort | sed -n '$p' | awk -F"BU" '{print $2}'`
echo "$k"
sleep 1
done


虽然写的搓了点，但能用

过过招

#!/usr/bin/env python3
import sys


with open('/root/1.txt') as f:
    l = f.readlines()
    nl = [[i.split('-')[0].replace('BU', ''), i.split()[1], i.split()[2]] for i in l]
    fl = [i for i in nl if sys.argv[1] <= i[2] <= sys.argv[2]]
    tml = sorted(list(set([i[2] for i in fl])))
    for i in tml:
        c1l = [int(j[0]) for j in fl if j[2] == i]
        max_c1 = max(c1l)
        for j in fl:
            if int(j[0]) == max_c1 and j[2] == i:
                print(' '.join(j))

sunceenjoy

1. awk '{if (a[$3] <= strtonum(substr($1, 3))) {a[$3]=strtonum(substr($1, 3));b[$3]=$2;}}END{for(i in a) print a[i], b[i], i;}' /tmp/1.txt

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