处理两个同样分隔符的行

seanking1987

假如有一个文本，内容如下：

1. ----------check1------------
   
2. check 1:
   
3. 10,20,30,40
   
4. -------------------------------
   
5. 
   
6. ----------check2------------
   
7. check 2:
   
8. 100,200,300,400
   
9. -------------------------------
   
10. 
    

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我希望找到check段信息里，第二列是否大于50，输出check段，check第二列的信息和判断值。
例如本例输出:
check1:20,0
check2:200,1

haooooaaa

1. awk -vRS='-+check[0-9]+-+' -F'[\n ,:]+' '{print $2$3":"$5","($4>50?1:0)}'

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Herowinter

回复 1# seanking1987

1. 
   
2. awk -F, '/check [0-9]+:/{s=$0;getline;print s""$2","($2>50?1:0)}' i
   
3. check 1:20,0
   
4. check 2:200,1
   

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moperyblue

1. awk -vRS= '{gsub(/[ -]/,"",$1);split($4,a,",");print $1":"a[2]","(a[2]>50?1:0)}'

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sunzhiguolu

1. perl -F/,/ -ane 'print $1 if(/\A(check\s+\S+)/);print "$F[1],",$F[1]>50||0,"\n" if(/\A\d/)' f

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check 1:20,0
check 2:200,1

liion631818

回复 1# seanking1987

1. awk -F, '$0~"-+check[0-9]-+"{gsub("-", ""); token=$0}$0~"^[0-9]+,"{print token":"$2","($2 > 50 ? 1 : 0)}'

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wjemail

]# grep -v "-" q13 | sed -ne '/check/ N' -e 's/:\n/:,/ p' | awk -F "," '{print $1$3","(($3>50? 1:0))}'
check 1:20,0
check 2:200,1