给每个makefile加prefix

linuxfellow

想给目录下每个package makefile加prefix
当前目录下有很多sub package, 每个子 package有一个目录，目录名字就是子package的名字
每个子目录下有一个名字为<sub_pack_name>.mk的makefile

要求寻找当前目录下所有 ./<sub_pack_name>/<sub_pack_name>.mk, 在./<sub_pack_name>/<sub_pack_name>.mk的第一个空行之后加下面一行：
   SUB_PACK_NAME_PREFIX =verity

例如有两个子包abc, def
./abc/abc.mk 里的第一个空行后加 ABC_PREFIX=verity
./def/def.mk  里的第一个空行后加 DEF_PREFIX=verity

shell scripts如何实现请高手帮忙！ 多谢！

jason680

回复 1# linuxfellow

$ find .
.
./def
./def/def.h
./def/def.mk
./def/def.c
./abc
./abc/abc.h
./abc/abc.mk
./abc/abc.c

$ find . -name "*.mk" | xargs grep ".*"
./def/def.mk:3
./def/def.mk:
./def/def.mk:4
./def/def.mk:
./def/def.mk:5
./abc/abc.mk:1
./abc/abc.mk:
./abc/abc.mk:2
./abc/abc.mk:
./abc/abc.mk:3

$ find . -name "*.mk" | xargs perl -i -lpe '{if(m/^\s*$/&&++$h{$ARGV,$c}==1){($F=uc$ARGV)=~s/(^.*\/|[.]MK$)//g;$_.="\n${F}_PREFIX=verity"}}'

$ find . -name "*.mk" | xargs grep ".*"
./def/def.mk:3
./def/def.mk:
./def/def.mk:DEF_PREFIX=verity
./def/def.mk:4
./def/def.mk:
./def/def.mk:5
./abc/abc.mk:1
./abc/abc.mk:
./abc/abc.mk:ABC_PREFIX=verity
./abc/abc.mk:2
./abc/abc.mk:
./abc/abc.mk:3


   

linuxfellow

回复 2# jason680
万分感谢！scripts很好用，问题解决了