处理时间

tannyzhou1

time=`ls -lctrE | tail -1 | awk '{print $6}'`
比如打出来为:2016-08-07
t=sed 's/\-//g' $time  本意想转换为: 20160807
为啥不成功？

jason680

回复 1# tannyzhou1

awk '{gsub("-","",$6);print $6}'


   

tannyzhou1

time_from_file=`ls -lctrE | tail -1 | awk '{print $6}'`
time_from_file=${time_from_file//\-/}

moperyblue

1. t=$(echo "$time"|sed 's/-//g') #或 t=`echo "$time"|sed 's/-//g'`  
   
2. echo $t
   
3. 20160807

复制代码

ll104567

root@lp:~/pwb/tmp/awk# echo $time
2016-08-07

root@lp:~/pwb/tmp/awk# echo $time|sed 's/-//g'
20160807

root@lp:~/pwb/tmp/awk# echo $time|awk '{gsub("-","")}1'
20160807

杰瑞26

root@localhost:~# time=2016-08-07

root@localhost:~# echo $time | sed 's/-//g'
20160807

root@localhost:~# echo $time | tr -d '-'
20160807

karma303

路过帮顶～～

RE_HASH

$>  time=2016-08-07; sed 's/-//g'<<<$time
20160807

sunzhiguolu

1. 
   
2. lt=2016-08-10
   
3. echo $lt|perl -F/-/ -nle 'print @F'

复制代码

20160810