怎么给每一行数据随机分配一个大于0.8小于1的概率

hxletter

比如说我们有如下数据

1. <p class="blockcode"><blockquote>a b c
   
2. d e f
   
3. g h i

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我想给每一行随机分配一个概率值, 变成

1. 
   
2. a b c 0.9
   
3. d e f 0.8
   
4. g h i  1
   
5. 
   
6. 
   
7. 
   

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应该怎么处理啊

zxy877298415

回复 1# hxletter

1. awk 'BEGIN{srand()}{t=gensub("<.*>","","",$0);while (1) {v=rand();if(v>0.8) break; } {printf "%s %.1f\n",t,v}}' file

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jason680

回复 1# hxletter

$ cat FILE
a b c
d e f
g h i

$ awk 'BEGIN{srand()}NF{$++NF=rand()*0.2+0.8}1' FILE
a b c 0.856056
d e f 0.837506
g h i 0.93951

$ awk 'BEGIN{srand()}NF{$++NF=rand()*0.2+0.8}1' FILE
a b c 0.845508
d e f 0.894413
g h i 0.99351

$ awk 'BEGIN{srand()}NF{$++NF=rand()*0.2+0.8}1' FILE
a b c 0.819001
d e f 0.971608
g h i 0.841237

moperyblue

1. echo 'a b c
   
2. d e f
   
3. g h i'|awk 'BEGIN{srand();split("0.8 0.9 1",a)}{$(NF+1)=a[int(rand()*2+1.5)]}1'

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