截取字符

jcdiy0601

回复 1# sauer

1. awk 'BEGIN{FS="[ &]+"}{sub("uid=","",$5);print $1,$2,$5}' file

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sditmaner

cat test04

victor2016

grep -Po '.*(?=/)|(?<=uid=)\d+(?=&type)' file |xargs

zl624867243

1. #!/usr/bin/python
   
2. #coding:utf8
   
3. import re
   
4. f = open("/root/d.txt",'r')
   
5. for i in f.readlines():
   
6.     result=re.findall("uid=(.*)&type.*",i)
   
7.     print i[0:8]+" "+i[9:22]+" "+result[0]
   
8. f.close()
   

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moperyblue

1. grep -oP '^(\s*\S+\s+){2}|uid=\K[^&]*'|xargs

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