awk统计某字段为空的在多少行

faith900

请问下这个怎么实现
a.txt
232,2131，,2123,23242
123,3341，22,3343,34343
324,2323, ,2334,23332


统计a.txt 的以逗号分隔第三个字段为空的，并打印出来
232,2131，,2123,23242
324,2323, ,2334,23332

moperyblue

有全角 半角的逗号?

1. echo '232,2131，,2123,23242
   
2. 123,3341，22,3343,34343
   
3. 324,2323, ,2334,23332'|sed -r '/^(([^,]*(，|,)){2})\s*(，|,)/!d;='|sed 'N;s/\n/\t/'

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fh21_xuejinlian

1. awk -F',' '$3==" "' file

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sunzhiguolu

1. perl -nle '@a=split/,|，/;print if($a[2]!~/\S/)' f

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elu_ligao

1. awk -F'[,，]' '!+$3'  

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jcdiy0601

1. awk -F, '{if($3~/[ ]+/){print}}' file

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zl624867243

1. #coding:utf8
   
2. import re
   
3. f = open("/root/d.txt",'r')
   
4. for i in f.readlines():
   
5.     t = re.split(",",i)
   
6.     if t[2]=="":
   
7.         print i
   
8. f.close()

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