[已解决]时间计算

聆雨淋夜

1. #/usr/bin/env python
   
2. # -*- coding: utf-8 -*-
   
3. 
   
4. 
   
5. from datetime import datetime,timedelta
   
6. import fileinput
   
7. for line in fileinput.input('test'):
   
8.     str1,str2,*_=line.strip('\n').split(' ')
   
9.     dt1=datetime.strptime(str1,'%H:%M:%S')
   
10.     dt2=datetime.strptime(str2,'%H:%M:%S')
    
11.     print(str1,str2,(dt2-dt1).seconds)
    

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jason680

回复 1# linuxbody

1 combine 3L and 4L
$ awk 'function s(x, t,n,r){t=split(x,a,":");r=a[1];for(n=2;n<=t;++n)r=r*60+a[n];return(r)}{print $0,s($2)-s($1)}' FILE
01:59:50 01:59:56 6
02:00:37 02:01:10 33
02:05:52 02:07:59 127


2. directly...
$ awk -F'[: ]+' '{print $0,($4*60+$5)*60+$6-(($1*60+$2)*60+$3)}' FILE
01:59:50 01:59:56 6
02:00:37 02:01:10 33
02:05:52 02:07:59 127