如果用for循环将类似这个文件格式的值取出来？

yabo300

ls_list+=(192.168.10.1:game1)
ls_list+=(192.168.10.2:game2)
ls_list+=(192.168.10.3:game3)
ls_list+=(192.168.10.4:game4)
ls_list+=(192.168.10.5:game5)

ip  192.168.10.5  目录 game5  id 5  每行要一一对应，求高手！！

moperyblue

1. sed -r 's/.*\((.*):([^0-9]+([0-9]+)).*/ip \1 目录 \2 id \3/'

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?

sunzhiguolu

game 后面接的是 ID 吗,

jason680

回复 1# yabo300

$ cat FILE
ls_list+=(192.168.10.1:game1)
ls_list+=(192.168.10.2:game2)
ls_list+=(192.168.10.3:game3)
ls_list+=(192.168.10.4:game4)
ls_list+=(192.168.10.5:game5)

$ awk '/ls_list/{if(match($0,"[(]([^:]+):([^)]+)[)]",a))print "ip",a[1],"目录",a[2],"id",++id}' FILE
ip 192.168.10.1 目录 game1 id 1
ip 192.168.10.2 目录 game2 id 2
ip 192.168.10.3 目录 game3 id 3
ip 192.168.10.4 目录 game4 id 4
ip 192.168.10.5 目录 game5 id 5

sunzhiguolu

1. #!/usr/bin/perl
   
2. use strict;
   
3. use warnings;
   
4. 
   
5. while (<DATA>){
   
6.         my @aT = grep (length, /([\d.]+)|(\w+(\d))/g);
   
7.         printf ("IP %s, Dir %s, ID %s\n", @aT);
   
8. }
   
9. 
   
10. __DATA__
    
11. ls_list+=(192.168.10.1:game1)
    
12. ls_list+=(192.168.10.2:game2)
    
13. ls_list+=(192.168.10.3:game3)
    
14. ls_list+=(192.168.10.4:game4)
    
15. ls_list+=(192.168.10.5:game5)
    

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sunzhiguolu

perl abc.pl
-----------------------
IP 192.168.10.1, Dir game1, ID 1
IP 192.168.10.2, Dir game2, ID 2
IP 192.168.10.3, Dir game3, ID 3
IP 192.168.10.4, Dir game4, ID 4
IP 192.168.10.5, Dir game5, ID 5

liying_gg

[admin@yh126 ~]$ cat 1
ls_list+=(192.168.10.1:game1)
ls_list+=(192.168.10.2:game2)
ls_list+=(192.168.10.3:game3)
ls_list+=(192.168.10.4:game4)
ls_list+=(192.168.10.5:game5)
[admin@yh126 ~]$ awk -F '[():]' '{print "ip "$2" 目录 "$3" id "FNR}' 1 1
ip 192.168.10.1 目录 game1 id 1
ip 192.168.10.2 目录 game2 id 2
ip 192.168.10.3 目录 game3 id 3
ip 192.168.10.4 目录 game4 id 4
ip 192.168.10.5 目录 game5 id 5

nonenull

1. sed -E  's/.*\((([0-9]{1,3}.){3}([0-9]{1,3})):(.*)\)/ip \1 dir \4 id \3/'

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zy86416779

1. [root@CentOS_6 experiment]# awk -F [\(:\)] '{split($2,array,"\.");printf("%-3s%-13s%-4s%-6s%-3s%-3s\n","ip",$2,"dir",$3,"id",array[4]);}' a.txt ^C
   
2. [root@CentOS_6 experiment]# cat a.txt
   
3. ls_list+=(192.168.10.1:game1)
   
4. ls_list+=(192.168.10.2:game2)
   
5. ls_list+=(192.168.10.3:game3)
   
6. ls_list+=(192.168.10.4:game4)
   
7. ls_list+=(192.168.10.5:game5)
   
8. [root@CentOS_6 experiment]# awk -F [\(:\)] '{split($2,array,"\.");printf("%-3s%-13s%-4s%-6s%-3s%-3s\n","ip",$2,"dir",$3,"id",array[4]);}' a.txt
   
9. awk: 警告: 转义序列“\.”被当作单纯的“.”
   
10. ip 192.168.10.1 dir game1 id 1  
    
11. ip 192.168.10.2 dir game2 id 2  
    
12. ip 192.168.10.3 dir game3 id 3  
    
13. ip 192.168.10.4 dir game4 id 4  
    
14. ip 192.168.10.5 dir game5 id 5

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