求一个代码

letwave

2009-11-12-02 570.6

2009-11-13-07 608

2009-12-24-00 392

2009-12-24-00 395

2010-02-07-22 544

2010-02-18-01 577.7

2010-03-20-14 414.6

2010-04-11-22 609.8

2010-05-24-16 581.2

2010-06-22-22 562.5

2010-07-23-22 578

2010-07-23-22 601.7

2010-07-23-22 607.1

2010-07-23-22 611.5

2010-07-23-23 640.6

2010-11-30-03 470

2011-03-10-17 510.6

2011-03-20-15 321

2011-04-03-14 551.7

2011-04-05-04 552.4

2011-05-10-15 544.6

2011-08-02-19 528.9

2011-08-11-01 496.8

如果第一列出现重复的时候，只取第一次出现的行。所以变为：

2009-11-12-02 570.6

2009-11-13-07 608

2009-12-24-00 392

2010-02-07-22 544

2010-02-18-01 577.7

2010-03-20-14 414.6

2010-04-11-22 609.8

2010-05-24-16 581.2

2010-06-22-22 562.5

2010-07-23-22 578

2010-07-23-23 640.6

2010-11-30-03 470

2011-03-10-17 510.6

2011-03-20-15 321

2011-04-03-14 551.7

2011-04-05-04 552.4

2011-05-10-15 544.6

2011-08-02-19 528.9

2011-08-11-01 496.8

谢谢啦！！

moperyblue

1. awk '!a[$1]++' file

复制代码

jason680

回复 1# letwave

http://bbs.chinaunix.net/thread-2309494-1-1.html