每38个字符分成一行

toddhai

数字空格小数点组成的文本，想要每38个字符为一行这样分割
举例：111  11111  11111111  11111111.22221212121212121212.12121.12121312321321312121212 12222    2222222 2222222 2222222222.22 222222 2222 22222222 2222   2222121212121212.12121.121213123213213121
想要的结果：
111  11111  11111111  11111111.2222121
2121212121212.12121.121213123213213121
21212 12222    2222222 2222222 2222222
222.22 222222 2222 22222222 2222   222
2121212121212.12121.121213123213213121

chengchow

1. [root@iZuf6e5osowhj2vbahat9wZ tmp]# awk -F "" '{for(i=1;i<=NF;i++){printf $i;if(i%38==0){printf "\n"}}}' aa.log
   
2. 111  11111  11111111  11111111.2222121
   
3. 2121212121212.12121.121213123213213121
   
4. 21212 12222    2222222 2222222 2222222
   
5. 222.22 222222 2222 22222222 2222   222
   
6. 2121212121212.12121.121213123213213121

复制代码

wh7211

回复 1# toddhai

1. awk -F "" '{for(i=1;i<=NF;i++){$i=i%38==0?$i"\n":$i;printf("%s",$i)}}' file

复制代码

sunzhiguolu

1. perl -0pe "s/(?|(.{38})|(.+))/$1\n/g" f

复制代码

REFRESHMM

cat 文本.txt |tr -d "\n" |grep -Eo '[0-9 .]{38}'  差最后一行

yinyuemi

fold                     

toddhai

回复 2# chengchow

厉害

toddhai

awk -F '' '{for(i=0;i<=NF/38;i++){for(j=1;j<=38;j++){printf "%s",$(j+i*3};printf "\n"}}' test.txt>test1.txt

expert1

]# fold --help
Usage: fold [OPTION]... [FILE]...
Wrap input lines in each FILE (standard input by default), writing to
standard output.

Mandatory arguments to long options are mandatory for short options too.
  -b, --bytes         count bytes rather than columns
  -c, --characters    count characters rather than columns
  -s, --spaces        break at spaces
  -w, --width=WIDTH   use WIDTH columns instead of 80
      --help     display this help and exit
      --version  output version information and exit

GNU coreutils online help: <http://www.gnu.org/software/coreutils/>
For complete documentation, run: info coreutils 'fold invocation'