求救：iconv函数用gcc和g++编译运行结果不同

akid

求救：为什么iconv函数通过gcc编译和通过g++编译出来的运行结果不一样啊？

测试结果：
$ gcc -o t t.c
$ g++ -o tt t.c
$./t
0xC4 0xE3 0xBA 0xC3
converting...
unicode=0xFF 0xFE 0x60 0x4F 0x7D 0x59
$ ./tt
0xC4 0xE3 0xBA 0xC3
converting...
unicode=0xFF 0xFE 0x60 0x4F 0x7D 0x59 0xFF 0xBF 0x30 0xF3 0xFF 0xBF 0xF8 0xA3

测试代码如下：
#include <iconv.h>;
#include <stdio.h>;
#include <string.h>;

#define CONV_BUF_LEN 1000

unsigned char itohex(unsigned char i)
{
if(i>;9) return i-10+'A';else return i+'0';
}

void outbin(char * pbuf) {
char *p = pbuf;
unsigned char ch;
if (!p)  return;
while (*p) {
   ch=*p;p++;
   printf("0x%c%c ", itohex(ch/16),itohex(ch%16));
}

printf("\n";
}

int gb2312_to_unicode(char* inbuf, char *outbuf)
{
        iconv_t cd;
        char* pin = inbuf;
        char* pout = outbuf;
        size_t inlen;
        size_t outlen = CONV_BUF_LEN - 1;

        outbin(inbuf);
        inlen = strlen(inbuf);
        if((cd = iconv_open("unicode","gb2312") < 0) return -1;
        printf("converting...\n";
        if(iconv(cd, &pin, &inlen, &pout, &outlen) < 0) return -1;
        iconv_close(cd);
        return 1;
}

int main()
{

  char inbuf[CONV_BUF_LEN];
  char outbuf[CONV_BUF_LEN];

  strcpy(inbuf,"你好";

  if(gb2312_to_unicode(inbuf,outbuf) >; 0) {printf("unicode=";outbin(outbuf);}
    else printf("fail:%s!\n",inbuf);
  return 1;
}